Question

我是python 3中的新手，我不明白为什么会出现类型错误（这是一个数字游戏，对于0到100之间的数字）：

print("Please think of a number between 0 and 100!")
low = 0 
high = 100
check = False
while True :
    guess = (low + high)/2
    print("Enter 'h' to indicate the guess is too high.\n")
    print("Enter 'l' to indicate the guess is too low.\n" )
    print("Enter 'c' to indicate I guessed correctly.\n")
    ans = input("")  
    if ans == "h" :
        low = ans
    elif ans == "l" :
       high = ans
    elif ans =="c" :
        print( "Game over. Your secret number was:{}".format(guess))
        break
    else :
        print("Sorry, I did not understand your input.")

这是错误：

Traceback (most recent call last):
 File "<stdin>", line 1, in <module>

先谢谢。我真的很感谢你的帮助我被困在这个

Answer 1

在low = ans行上，您将低值设置为字符串值，字符串值为＆＃34; h＆＃34;

然后在第二次通过循环时，尝试计算 (low + high）/ 2`您无法计算（＆＃34; h＆＃34; + 100）/ 2，因为您无法将字符串添加到整数。这是＆＃34;类型错误＆＃34;

每一行向朋友（或软玩具）解释每一行的作用以及为什么你确定每一行都是正确的。

Answer 2

有几件事。

您应该打印猜测，以便用户知道它是太高还是太低
low==ans没有任何意义。假设用户遵守规则，ans将是＆＃34; h＆＃34;，＆＃34; l＆＃34;或＆＃34; c＆＃34; low和high需要为数字才能正确生成guess

你的逻辑也是错误的。以下代码有效。

print("Please think of a number between 0 and 100!")
low = 0
high = 100
check = False
while True:
    guess = (low + high)/2
    print("My guess is: %i" % guess)
    ans = input("Enter 'h' if guess it too high, 'l' if too low, or 'c' if correct: ")
    print(ans)
    if ans == "h":
        high = guess
    elif ans == "l":
        low = guess
    elif ans == "c":
        print("Game over. Your secret number was:{}".format(guess))
        break
    else:
        print("Sorry, I did not understand your input.")

Python 3：回溯：TypeError

2 个答案: