Question

我正在尝试使用ajax提交表单，因此我的页面不会执行full page reload，而只是表单应更改以显示任何错误。我从网上尝试了很多选项而没有运气。这here是我见过的最好的帮助，but它没有给出解决方案。 Note I am using laravel version 5.3.10。

这是我的代码：

Javascript:

<script type="text/javascript">

    $(document).ready(function () {

        $('#footer-form').click(function () {
            //event.preventDefault();
            $.ajax({
                type: 'POST',
                url: 'http://localhost/ensignhospital/mail',
                data: $('form#footer-form').serialize(),
                dataType: 'html'
            })

                    .done(function (data) {
                        console.log(data);
                    });

        });
    });

</script>

Laravel Route:

Route::group(['before' => 'guest'], function () {
    /*
     * CSRF Protection
     *
     * */
    Route::group(['before' => 'csrf'], function () {

        Route::post('/ensignhospital/mail', [
            'as' => 'mail',
            'uses' => 'HomeController@postSendMail'
        ]);
    });


});

Laravel controller:

 public function postSendMail(Request $request)
    {

        if($request->ajax()){

            $validator = Validator::make($request->all(), [

                'first_name' => 'required',
                'last_name' => 'required',
                'email' => 'required|email',
                'message' => 'required',
                'g-recaptcha-response' => 'required|captcha'
            ]);

            if($validator->fails()){
                return redirect()->back()
                    ->withErrors($validator)
                    ->withInput(Input::all());
            }else{
                return View('passed');

            }
        }else{
            return View('fail');
        }



    }

Form:

{!! Form::open(['route' => 'mail', 'method' => 'post', 'role' => 'form', 'id' => 'footer-form']) !!}
<div class="form-group has-feedback">
    {!! Form::label('first_name', null, ['class' => 'sr-only']) !!}
    {!! Form::text('first_name', null, ['class' => 'form-control', 'placeholder' => 'First Name']) !!}
    <i class="fa fa-user form-control-feedback"></i>
    @if($errors->has('first_name'))
        {{ $errors->first('first_name') }}
    @endif
</div>
<div class="form-group has-feedback">
    {!! Form::label('last_name', null, ['class' => 'sr-only']) !!}
    {!! Form::text('last_name', null, ['class' => 'form-control', 'placeholder' => 'Last Name']) !!}
    <i class="fa fa-user form-control-feedback"></i>
    @if($errors->has('last_name'))
        {{ $errors->first('last_name') }}
    @endif
</div>
<div class="form-group has-feedback">
    {!! Form::label('email', null, ['class' => 'sr-only']) !!}
    {!! Form::email('email', null, ['class' => 'form-control', 'placeholder' => 'Email address']) !!}
    <i class="fa fa-envelope form-control-feedback"></i>
    @if($errors->has('email'))
        {{ $errors->first('email') }}
    @endif
</div>
<div class="form-group has-feedback">
    {!! Form::label('message', null, ['class' => 'sr-only']) !!}
    {!! Form::textarea('message', null, ['class' => 'form-control', 'rows' => 8, 'placeholder' => 'Message']) !!}
    <i class="fa fa-pencil form-control-feedback"></i>
    @if($errors->has('message'))
        {{ $errors->first('message') }}
    @endif
</div>    

{!! Form::submit('Send', ['class' => 'btn btn-default', 'id' => 'mail_btn']) !!}

{!! Form::close() !!}

Answer 1

您需要做的是渲染您希望通过ajax传递的视图，如下所示：

return view('passed')->render();

...

return view('fail')->render();

修改

您必须将event作为clouser参数传递并取消注释：//event.preventDefault();：

$('#footer-form').click(function (event) { event.preventDefault(); $.ajax({ type: 'POST', url: 'http://localhost/ensignhospital/mail', data: $('form#footer-form').serialize(), dataType: 'html' }) .done(function (data) { console.log(data); }); });

这样：

click(function () {

为什么它不起作用。应该是：

click(function (event) {

使用laravel和ajax重新加载部分页面

1 个答案: