我在oracle中有一个table1(startnumber,endnumber);
现在我需要从table1
中选择startnumber和endnumber之间的所有数字数据,例如
table1
startnumber endnumber
10 15
18 22
34 50
Now I need the result set as:
10,11,12,13,14,15,18,19,20,21,22,34,35..... and so on
我该怎么做
答案 0 :(得分:3)
如果您希望以逗号分隔值,则可以这样做(或者如果在11gr2上使用listAgg)
WITH NUMS AS(
SELECT 10 STARTNR , 15 ENDNR FROM DUAL UNION
SELECT 18 STARTNR , 22 ENDNR FROM DUAL UNION
SELECT 34 STARTNR , 50 ENDNR FROM DUAL ) ,
NUMSBETWEEN AS(
SELECT distinct (level + startnr)-1 seq , startnr, endnr
FROM NUMS
CONNECT BY (LEVEL +STARTNR ) <= ENDNR+1
)
SELECT startnr,
LTRIM(MAX(SYS_CONNECT_BY_PATH(seq,','))
KEEP (DENSE_RANK LAST ORDER BY curr),',') AS seq
FROM (SELECT startnr,
seq,
ROW_NUMBER() OVER (PARTITION BY startnr ORDER BY seq) AS curr,
ROW_NUMBER() OVER (PARTITION BY startnr ORDER BY seq) -1 AS prev
FROM numsBetween)
GROUP BY startnr
CONNECT BY prev = PRIOR curr AND startnr = PRIOR startnr
START WITH CURR = 1;
STARTNR SEQ
10 10,11,12,13,14,15
18 18,19,20,21,22
34 34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50
答案 1 :(得分:2)
SQL> ed
Wrote file afiedt.buf
1 with t as (
2 select 10 startnum, 15 endnum from dual
3 union all
4 select 18, 22 from dual
5 union all
6 select 34, 50 from dual
7 )
8 select lvl
9 from (select level lvl
10 from dual
11 connect by level <= (select max(endnum) from t)) a
12 where exists (select 1
13 from t
14* where lvl between t.startnum and t.endnum)
SQL> /
LVL
----------
10
11
12
13
14
15
18
19
20
21
22
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
28 rows selected.
如果最低起始数与最大结束数相比相对较大,则可以更改CONNECT BY子查询以生成从MIN(起始编号)到MAX(结束编号)的数字,而不是从1到MAX(结束编号),这应该是更有效率。