Question

我想使用JTextField方法验证我的其他InputVerifier。我做了什么我使用JTextField为其他setName设置了一个名字。

private void validateJTextField()
{
    tfAddress.setName("tfAddress");
    tfLastName.setInputVerifier(new Validation());
    tfFirstName.setInputVerifier(new Validation());
    tfMiddleName.setInputVerifier(new Validation());
    tfNickname.setInputVerifier(new Validation());
    tfAddress.setInputVerifier(new Validation());
}

验证类

public class Validation extends InputVerifier
{  
@Override
public boolean verify(JComponent input) 
{

    String text = null;
    String name = input.getName();
    if(input instanceof JTextField)
    {
        text = ((JTextField) input).getText();
        if(text.trim().length() == 0 || text.equals(""))
        {
            JOptionPane.showMessageDialog(null, "Cannot left blank");
            return false;//Return false if the component need to keep focus
        }

        else
        {
            try
            {
                Double.parseDouble(text);
                JOptionPane.showMessageDialog(null, "Cannot insert numeric");
                return false;
            }
            catch(NumberFormatException e)
            {

            }
        }

     if(text.equals("") && name.equals("tfAddress"))
     { 
        System.out.print("This is tfAddress");
        return false;
     }

    }

    return true;//Return true if the component should give up focus
}
}

正如您在此处所见，我正在尝试验证或检查name字符串是否等于"tfAddress"但不幸的是它不符合条件。任何帮助或提示如何解决这个问题？

Answer 1

在您的代码中，此语句if(text.equals("") && name.equals("tfAddress"))永远不会满足，因为if(text.trim().length() == 0 || text.equals(""))检查，因此text.equals("")永远不会返回true，因此name.equals("tfAddress")将跳过。

在if子句的第一次检查中，如果文本为空，则代码将返回。因此，if(text.equals("") && name.equals("tfAddress")) if(name.equals("tfAddress"))可以检查dom4j-1.6.1.jar poi-3.11.jar poi-ooxml-3.11.jar poi-ooxml-schemas-3.15-beta2.jar xmlbeans-2.6.0.jar poi-scratchpad-3.11.jar poi-excelant-3.11.jar

Answer 2

我刚刚解决了这个问题。我在逻辑上犯了一个错误。我基于text.trim().length() == 0 || text.equals("")所以当程序运行时，首先检查文本是否为空。我做了什么我根据setName方法设置条件。希望这会对其他人有所帮助。

private void validateJTextField()
{
    tfLastName.setName("tfLastName");
    tfFirstName.setName("tfFirstName");
    tfMiddleName.setName("tfMiddleName");
    tfNickname.setName("tfNickname");
    tfAddress.setName("tfAddress");
    tfContact.setName("tfContact");
    tfLastName.setInputVerifier(new Validation());
    tfFirstName.setInputVerifier(new Validation());
    tfMiddleName.setInputVerifier(new Validation());
    tfNickname.setInputVerifier(new Validation());
    tfAddress.setInputVerifier(new Validation());
    tfContact.setInputVerifier(new Validation());
}

public class Validation extends InputVerifier
{  
@Override
public boolean verify(JComponent input) 
{
    String text = null;
    String cb = null;
    String name = input.getName();
    if(input instanceof JTextField)
    {
        text = ((JTextField) input).getText();

        if(name.equals("tfLastName") || name.equals("tfFirstName") || name.equals("tfMiddleName") || name.equals("tfNickname"))
        {
            if(text.trim().length() == 0 || text.equals(""))
            {
                JOptionPane.showMessageDialog(null, "Cannot left blank");
                return false;//Return false if the component need to keep focus
            }
            else
            {
                try
                {
                    Double.parseDouble(text);
                    JOptionPane.showMessageDialog(null, "Cannot insert numeric");
                    return false;
                }
                catch(NumberFormatException e)
                {

                }
            }
        }
        else if(name.equals("tfAddress"))
        {
            if(text.trim().length() == 0 || text.equals(""))
            {
                JOptionPane.showMessageDialog(null, "Cannot left blank");
                return false;//Return false if the component need to keep focus
            }
        }
}

getName方法无法从其他类

2 个答案: