我是一名新的yii2开发人员! 我制作了一个GridView,代码如下所示:
<?php Pjax::begin(); ?> <?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\ActionColumn'],
['class' => 'yii\grid\CheckboxColumn'],
['class' => 'yii\grid\SerialColumn'],
'id',
'countryCode',
'countryName',
'currencyCode',
],
]); ?>
<?php Pjax::end(); ?>
输出截图: OUTPUT
现在我希望有一个列包含一些按钮,该按钮例如打开一个页面或其他东西! 我的问题是如何创建该列?
答案 0 :(得分:7)
您也可以将按钮(或任意多个)添加到现有的操作列中,如下所示
<?= GridView::widget([
::
::
'columns' => [
[
'class' => 'yii\grid\ActionColumn',
'template' => '{view} {update} {delete} {myButton}', // the default buttons + your custom button
'buttons' => [
'myButton' => function($url, $model, $key) { // render your custom button
return Html::a(..);
}
]
]
::
::
'currencyCode'
]
]); ?>
答案 1 :(得分:0)
示例:
<?php Pjax::begin(); ?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\ActionColumn'],
['class' => 'yii\grid\CheckboxColumn'],
['class' => 'yii\grid\SerialColumn'],
'id',
'countryCode',
'countryName',
'currencyCode',
[
'label' => 'My Label',
'format' => 'raw',
'value' => Html::a('Click me', ['site/index'], ['class' => 'btn btn-success btn-xs', 'data-pjax' => 0])
]
],
]); ?>
<?php Pjax::end(); ?>
答案 2 :(得分:0)