Question

有人可以帮我找到我的代码中的问题吗？我试图根据它的网址将<span class="file-wrapper pointer">  <span class="btn_upload" onclick="$('#profileFile').click();"><i class="fa fa-camera pointer"></i></span> <input type="file" id="profileFile" name="profileFile" style="display:none;" file-model="profileImage" upload-after-changed="uploadProfile()"> </span>设置为有效。但问题是加载后没有任何设置为活动状态。请告诉我如何做到这一点或任何其他方法来做到这一点？

注意 li有空格。 $subj_descr，COMPUTER PROGRAMMING 1

这里是ENGLISH 2和li找到的PHP代码。

这是我的js

<li data-popover="true" rel="popover" data-placement="right"><a href="#" data-target=".premium-menu" class="nav-header collapsed" data-toggle="collapse"><i class="fa fa-fw fa-book"></i> Lectures<i class="fa fa-collapse"></i></a></li>
    <li><ul id="wa" class="premium-menu nav nav-list collapse in">
    <?php
         $sql ="SELECT enroll_ref FROM std_enrolled WHERE stud_no = '$stud_no'";
           $result = mysqli_query($con, $sql);

           while($row = mysqli_fetch_array($result)){
            $enroll_ref = $row['enroll_ref'];
             }



              $sql3 ="SELECT DISTINCT subj_descr FROM subj_enrolled WHERE enroll_ref = '$enroll_ref'";
           $results = mysqli_query($con, $sql3);

           while($row = mysqli_fetch_array($results)){
            $subj_descr = $row['subj_descr'];

    ?>

        <li id="<?php echo $subj_descr; ?>" ><a href="viewlecture.php?subjdescr=<?php echo $subj_descr;?>"><span class="fa fa-caret-right"></span><?php echo ucwords(strtolower($subj_descr)); ?></a></li>
     <?php
      }  
     ?>
</ul></li>

Answer 1

您可以尝试使用以下代码：

$(document).ready(function() {

    $(function(){
        //location.search will give us query string i.e. part present after ? mark and ? itself which is nothing but ?subjdescr=COMPUTER PROGRAMMING 1 
        var current = decodeURIComponent(location.search); //decodeURIComponent to decode white space chars like %20 will get converted to white space 
        alert(current);
        $('#wa li a').each(function(){
            var $this = $(this);

            alert(decodeURIComponent($this.attr('href')));

            // if the current path is like this link, make it active
            if(decodeURIComponent($this.attr('href')).indexOf(current) !== -1){

                $this.closest("li").addClass('active'); //setting the active class to parent li and not to a tag

            }
        })
    })
});

我想您需要将active设置为li代码而不是<a>，所以只需通过$.closest()

抓住它

注意：添加decodeURIComponent()以避免字符串比较中的编码字符

Answer 2

请尝试。

将lst[[ lst[[1]] ]]替换为location.pathname。

window.location.href

Answer 3

您可以使用它来查找URL

中的文本

 var my_url = "localhost/studentportal/viewlecture.php?subjdescr=COMPUTER%20PROGRAMMING%202";
        var found_my_url = my_url.search("viewlecture.php");
        var found_hashed = my_url.search("\\?");
        if(found_my_url!=-1 && found_hashed!=-1)
        {
    var url_split = my_url.split("?");
    var url_final = url_split[1].split("=");
    if(url_final[1]=="COMPUTER%20PROGRAMMING%202")
    {
    alert("Found in the URL");
    }
    else
    {
    alert("NOT FOUND in the URL");
    }
    }

根据网址设置li有效

3 个答案: