如何让它循环以查看它们是否有多于一个词要翻译?我认为我已经走上了正确的道路,重复它,不得不错过一个我无法看到的小细节。
谢谢!
所以这是我的代码:
import java.util.Scanner;
public class holdingCode
{
public static void main (String[] args)
{
System.out.println("Please enter a word to be translated: ");
Scanner in = new Scanner(System.in);
//Grabs a word for the user to translate further down
String answer = "";
do
{
String newWord = in.nextLine();
newWord = newWord.toUpperCase();
char vowel = Character.toLowerCase(newWord.charAt(0));
if (vowel == 'a' || vowel == 'e' || vowel == 'i' || vowel == 'o' || vowel == 'u')
{
String pigLatinWay = newWord + "WAY";
System.out.println("Your word in pig latin is " + pigLatinWay + ".");
System.out.println("Do you have another word to translate? (Y/N)");
answer = in.nextLine();
//converts if it is a vowel
}//end of if code
else
{
if (true)
{
String first = newWord.substring(0,1);
String slice = newWord.substring(1,newWord.length());
System.out.println(" Your translated word is " + slice + first + "AY");
System.out.println("Do you have another word to translate? (Y/N)");
answer = in.nextLine();
//converts if it isn't a vowel
}//end of if code
}//end of else code
}
while (answer.equalsIgnoreCase("Y"));
}//end of pigLatin
}//end of program
答案 0 :(得分:0)
String anwser = in.nextLine();
的范围仅限于
所以试试
后
newWord = newWord.toUpperCase();
String answer = "";
块中的
anwser = in.nextLine();
最后你的比较
while (anwser.equalsIgnoreCase("Y"));
修改强>
总结一下,你可以做到
String answer;
do
{
String newWord = in.nextLine();
newWord = newWord.toUpperCase();