Question

好吧，出于某种原因，如果不这样做，我总是会收到该电子邮件。

public function emailExists($mail) {
            $handler = new sql();
            $sql = $handler->connect();

            $sql->real_escape_string($mail);

            $result = $sql->query("SELECT email FROM users WHERE email='".$mail."'");



            if($result->num_rows != 0) return true;
            else {
                $handler->log_write($mail, "register_fail","NULL");
                return false;
            }
            $sql->close();
            return false;
        }

现在是支票

if($user->emailExists() == false) {
        $user->create($name, $pass,  $email, $age, $gender);
            jquery_alert("You have been registered. Thank you for using our services. Enjoy your stay!");
            jquery_reload();
        }
        else {
            jquery_alert("This email already exists");
        }

Answer 1

将电子邮件地址作为方法中的参数传递。

if($user->emailExists($email) == false) {
// your code here
}

Answer 2

在您的函数中，返回的默认值为false

并在您的方法中传递电子邮件地址。

试试这个解决方案

if($user->emailExists($email) == true) {
    $user->create($name, $pass,  $email, $age, $gender);
        jquery_alert("You have been registered. Thank you for using our services. Enjoy your stay!");
        jquery_reload();
    }
    else {
        jquery_alert("This email already exists");
    }

电子邮件已经存在

2 个答案: