Question

我有 Exec 实体：

@Entity("Exec")
public class Exec {
  @Id
  private ObjectId id;
  private long initDate;
  private long endDate;
  public enum statuses {
    SUCCESS, FAIL, PARTIAL
  }
  private statuses status;
  @Reference(idOnly = true, ignoreMissing = true, lazy = false)
  Analysis analysis;
  @Reference(idOnly = true, ignoreMissing = true, lazy = true)
  Set<Conclusion> conclusions = new HashSet<Conclusion>();
  // getters and setters

引用了结论实体：

@Entity("Conclusion")
public class Conclusion {
  @Id
  private ObjectId id;
  private Map<String, Object> params = new HashMap<String, Object>();
  private long initDate;
  private long endDate;
  public enum statuses {
    SUCCESS, 
    FAILURE
  }
  private statuses status; 
  private String errorMessage;
  private String stackTrace;
  Set<Map<String, Object>> data = new HashSet<Map<String, Object>>();

在调试器中，如果我试图得出结论

Set<Conclusions> conclusions = mongoWrapper.getDataStore().createQuery(Exec.class).asList().get(0).getConclusions()

我收到以下消息：

com.sun.jdi.InvocationException occurred invoking method.

如果我尝试访问该对象，例如，执行以下操作：

conclusions.toArray()

它抛出RuntimeException，检查堆栈跟踪：

org.mongodb.morphia.mapping.MappingException: Embedded element isn't a DBObject! How can it be that is a class java.lang.String

我尝试改变一堆东西，没有什么真正有效。关于问题的关键是什么想法？

Answer 1

在一组结论中使用具体的AnalysisConclusion。请记住，注释不是继承的，然后使用@Entity

标记AnalysisConclusion

使用Morphia获取@reference实体时出错

1 个答案: