Question

我有一个T-SQL查询，它返回两行具有相同联系人姓名的结果但在其中一列中不同：

Contact Name   BuildingID    ClassID
------------------------------------
XXXX              720         3505
XXXX              720         3650

我需要将ClassID两个值组合到ClassID列中，如下所示：

Contact Name   BuildingID    ClassID
----------------------------------------
XXXX              720        3505;3650

Answer 1

你可以尝试使用stuff和xml Path

SELECT ContactName, BuildingID,
   STUFF((SELECT ','+CONVERT(varchar(20),classid) FROM Contacts where contactname= c.ContactName and BuildingId = c.BuildingID
           FOR XML PATH('')),1,1,'') AS ClassId
FROM Contacts C
Group by ContactName, BuildingId

Answer 2

SELECT *
FROM schema.table
WHERE src_id IN (
    SELECT DISTINCT src_id
    FROM schema.table
    WHERE batch_id = ?
        AND cand_source = 'mcp'
)
ORDER BY src_id,
    match_score DESC

Answer 3

如果您需要超过1次联系＆amp;建设，然后这应该工作：

select [Contact Name], BuildingId,
STUFF(
  (   SELECT concat(';',ClassId)
      FROM YourTable t2
      WHERE t1.[Contact Name] = t2.[Contact Name] 
        AND t1.BuildingId = t2.BuildingId
      ORDER BY ClassId
      FOR XML PATH('') , TYPE
  ).value('.', 'varchar(max)'),1,1,''
) as ClassIds
from YourTable t1
--where [Contact Name] = 'XXXX' and BuildingId = 720
group by [Contact Name], BuildingId;

并将它变成一个只有1家公司的变量＆amp;建筑？
这是一个小技巧：

declare @ClassIds varchar(max);
declare @ContactName varchar(30) = 'XXXX';
declare @BuildingId int = 720;    

select @ClassIds = concat(@ClassIds+';',ClassId) 
from YourTable 
where [Contact Name] = @ContactName and BuildingId = @BuildingId
order by ClassId;

select @ContactName as [Contact Name], @BuildingId as BuildingId, @ClassIds as ClassIds;

T-SQL查询附加列

3 个答案: