Question

我已经给出了一个像下面这样的条件，它无法匹配from table1;或insert into table1(col1,col2 ..)

这样的行

if(Arrays.asList(line.split("\"")).contains("table1")) || 
        Arrays.asList(line.split(" ")).contains("table1"))
    System.out.println(line);

我需要遵循哪种逻辑？

Answer 1

使用正则表达式并将所需的所有特殊字符放在该表达式中。

<statement-card>
    <statement-card-title>
        <div class="schedule-statement-title">Payment schedule</div>
    </statement-card-title>
    <statement-card-summary>
        <h4 class="statement-card-section-title">Payment frequency:</h4>
        <div>
            {{frequency}}
        </div>
        <div>
            Next payment: {{payment?.scheduledDate | date:'MMMM dd, yyyy'}}
        </div>
    </statement-card-summary>
    <statement-card-addition>
        <h4 class="statement-card-section-title">Payment amount:</h4>
        <div class="addition-line"><span>Amount</span><span>{{payment?.amount}}</span></div>
        <div class="addition-line"><span>Sales tax</span><span>{{payment?.salesTax}}</span></div>
        <hr class="addition-seperator" />
        <div class="addition-total"><span>Total</span><span>{{getPaymentTotal()}}</span></div>
    </statement-card-addition>
    <statement-card-payment-method>
        <h4 class="statement-card-section-title">Payment method:</h4>
        <img src="images/bank.png" width="48" height="48" class="payment-method-icon" />
        <div class="payment-method-summary">
            <div>Bank</div>
            <div>Account ending in  ••••••••••1234</div>
        </div>
    </statement-card-payment-method>
    <statement-card-interactions>
        <div class="row">
            <div class="col-md-6">
                <a href="#" class="pull-right">MAKE A PAYMENT</a>
            </div>
            <div class="col-md-6">
                <a href="#" class="pull-right">VIEW PAYMENT SCHEDULE</a>
            </div>
        </div>
    </statement-card-interactions>
</statement-card>

Answer 2

使用正则表达式匹配，如下所示

foreach

请注意，您可以在方括号中放置要分割线条的任何字符。

Answer 3

试试这个：

if (Arrays.asList(list.split("[^a-zA-Z0-9_]")).contains("table1")) {
        System.out.println(list);
}

或者，因为RealSkeptic建议使用正则表达式匹配：

if (list.matches(".*\\btable1\\b.*")) {
        System.out.println(list);
}

Answer 4

您可以使用正则表达式：

    Pattern pat = Pattern.compile("(?<!\\p{L})table1(?!\\p{L})");
    if (pat.matcher(line).find())
    {
      System.out.println(line);
    }

Answer 5

如果我理解你的问题，你可以在不使用Splits的情况下实现它：

 String stringPattern = ".*table1.*";
 Pattern pattern = Pattern.compile(stringPattern);
 Matcher matcher = pattern.matcher(line);
 if (matcher.matches())
  System.out.println(line);

Answer 6

您可以使用带有负面外观和负面外观的正则表达式：

String input = "from table1;";
Pattern p = Pattern.compile("(?<![a-zA-Z0-9_])table1(?![a-zA-Z0-9_])");
Matcher matcher = p.matcher(input);

if (matcher.find()) 
    System.out.println(input);

这将匹配任何"table1"出现的任何字母，数字或_符号之前或之后的出现。

如何匹配具有直接特殊字符的行中的字符串？

6 个答案: