Question

我的SQL查询

select status,count(id) from table group by status;

返回以下数据

Resolved- 4
Closed - 12
Verified - 3
New* - 23
Unconfirmed* - 4
Needmoreinfo* - 5.

我希望mysql返回的是

Resolved- 4
Closed - 12
Verified - 3
Found* - 32

即新的，未经证实的，Needmoreinfo应被视为＆＃39;发现＆＃39;

Answer 1

你的问题缺少帮助你的信息..但也许你想要这个

SELECT 
CASE WHEN (status NOT IN ('Resolved', 'Closed', 'Verified')) THEN 'Found*' ELSE status END as status, count(id) 
FROM table 
GROUP BY CASE WHEN (status NOT IN ('Resolved', 'Closed', 'Verified')) THEN 'Found*' ELSE status END

Answer 2

首先，我们要改变你的表格，即添加一个额外的列 LTER TABLE yourtable ADD COLUMN Found VARCHAR（50）;

更新youtedable SET Found = CONCAT（New，＆＃39; - ＆＃39;，未确认，＆＃39;，＆＃39;，Needmoreinfo）;

现在你可以编写选择查询

将多个字段数据分组为sql中的一个字段

2 个答案: