IOS提供Viewcontroller并在editActionsForRowAt

Question

您好我正在使用tableview单元格中的自定义操作开发应用程序。

当用户滑动单元格时。将有2个动作：删除等等。我想要更多动作来呈现一个新的viewController并将对象数据传递给新的viewController。我们如何实现这一目标？

我尝试过使用此

viewDidLoad

中的

if let split = self.splitViewController {
            let controllers = split.viewControllers
            self.detailViewController = (controllers[controllers.count-1] as! UINavigationController).topViewController as? DetailViewController
        }

和editActionsForRowAt方法

override func tableView(_ tableView: UITableView, editActionsForRowAt indexPath: IndexPath) -> [UITableViewRowAction]? {

        let moreRowAction = UITableViewRowAction(style: .normal, title: "More", handler:{action, indexpath in

            if let indexPath = self.tableView.indexPathForSelectedRow {
                let object = self.fetchedResultsController.object(at: indexPath)
                let controller = self.detailViewController!
                controller.detailItem = object
                controller.navigationItem.leftBarButtonItem = self.splitViewController?.displayModeButtonItem
                controller.navigationItem.leftItemsSupplementBackButton = true
                self.present(controller, animated: true, completion: nil)
            }
//                self.performSegue(withIdentifier: "showDetail", sender: self)
        });
        moreRowAction.backgroundColor = UIColor(red: 0.298, green: 0.851, blue: 0.3922, alpha: 1.0);

        let deleteRowAction = UITableViewRowAction(style: .destructive, title: "Delete", handler:{action, indexpath in
            self.deleteTapped(indexPath: indexPath as NSIndexPath)
        });

        return [deleteRowAction, moreRowAction];
    }

删除功能可以正常工作，但更多操作不起作用。非常感谢帮助！感谢

我的prepareforseuge

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "showDetail" {
            if let indexPath = self.tableView.indexPathForSelectedRow {
            let object = self.fetchedResultsController.object(at: indexPath)
                let controller = (segue.destination as! UINavigationController).topViewController as! DetailViewController
                controller.detailItem = object
                controller.navigationItem.leftBarButtonItem = self.splitViewController?.displayModeButtonItem
                controller.navigationItem.leftItemsSupplementBackButton = true
            }
        }
    }

Answer 1

您可以通过sender参数将对象传递给segue：

let moreRowAction = UITableViewRowAction(style: .normal, title: "More", handler:{action, indexpath in
        let object = self.fetchedResultsController.object(at: indexPath)
        self.performSegue(withIdentifier: "showDetail", sender: object)
    });

然后在prepare(for segue: sender:) -

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "showDetail" {
        guard let navVC = segue.destination as? UINavigationController,
            let destVC = navVC.viewControllers.first as? DetailViewController else {
                return
        }

        var object = sender as? Event
        if object == nil {
            if let indexPath = self.tableView.indexPathForSelectedRow {
                object =  self.fetchedResultsController.object(at: indexPath)
            }
        }
        destVC.detailItem = object
    }
}

Master-Detail模板项目使用导航控制器作为详细目的地，因此prepare(for segue)功能需要访问导航控制器的第一个视图控制器。

此外，由于您使用相同的segue进行行点击和“更多”操作，我的代码会检查两种可能性 - 详细信息项可能位于发件人或所选行中