Question

我正在尝试创建一个字典，其中包含一个值为＆＃39; Object_Info＆＃39;的键。我有以下代码并得到此错误：

Incompatible pointer types initializing 'NSMutableDictionary *' with an expression of type 'NSDictionary *'

这是我的代码：

#import <Foundation/Foundation.h>

@interface Object_Info : NSObject
{
    NSString *product;
    float cost;
    int qty;
}
@end


@implementation Object_Info

-(id) init {
    if (self = [super init]){
        product = @"";
        cost = 0.0;
        qty = 0;      
    }
    return self;
}
@end

int main(int argc, const char * argv[]) {
    @autoreleasepool {
          NSMutableDictionary *stock = @{ //ERROR IS HERE!!!!!
                                @"Lawn Chair" : [Object_Info new],
                                @"Beach Chair" : [Object_Info new],
                                @"Kitchen Chair" : [Object_Info new],
                                @"Futon" : [Object_Info new],
                                };

        for(NSString *key in [stock allKeys]) {
            NSLog(@"%@",[stock objectForKey:key]);
        }

    }
    return 0;
}

Answer 1

您遇到的问题是您正在尝试将NSDictionary分配给NSMutableDictionary。

试试这个：

NSMutableDictionary *stock = [NSMutableDictionary new];
[stock setDictionary:@{
                                                @"Lawn Chair" : [Object_Info new],
                                                @"Beach Chair" : [Object_Info new],
                                                @"Kitchen Chair" : [Object_Info new],
                                                @"Futon" : [Object_Info new],
                                                }];

我必须创建一个可变字典，但我得到一个＆＃34;不兼容的指针类型初始化＆＃34;错误

1 个答案: