我想发送一个请求并从它的cookie中获取XSRF-TOKEN,当我将POST发送到寄存器时,我想把它放入标题中。其实我想做点什么:access laravel app from android app with csrf token
我正在使用StringRequest发送这样的请求:
private void registerUser(final String name, final String email,
final String password,final String confirm) {
// Tag used to cancel the request
String tag_string_req = "req_register";
pDialog.setMessage("Registering ...");
showDialog();
final StringRequest strReq = new StringRequest(Request.Method.POST,
AppConfig.URL_REGISTER, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
datares = response;
Log.d("REGISTER RESPONSE", "Register Response: " + response.toString());
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Registration Error: " + error.getMessage());
Toast.makeText(getActivity().getApplicationContext(),
error.getMessage(), Toast.LENGTH_LONG).show();
hideDialog();
}
}) {
@Override
protected Map<String, String> getParams() {
// Posting params to register url
Map<String, String> params = new HashMap<String, String>();
params.put("name", name);
params.put("email", email);
params.put("password", password);
params.put("password-confirm",confirm);
return params;
}
};
// Adding request to request queue
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
AppController.java
public static synchronized AppController getInstance() {
return mInstance;
}
public RequestQueue getRequestQueue() {
if (mRequestQueue == null) {
mRequestQueue = Volley.newRequestQueue(getApplicationContext());
}
return mRequestQueue;
}
public <T> void addToRequestQueue(Request<T> req, String tag) {
req.setTag(TextUtils.isEmpty(tag) ? TAG : tag);
getRequestQueue().add(req);
}
你知道我怎么能用Volley做到这一点?
答案 0 :(得分:2)
这是一个迟到的答案。无论如何,如果有人偶然发现这里寻找任何答案,我会在这里添加其中一种方式:)
您可以使用csrf_exempt。它将免除CSRF考虑的观点。我不确定这是否是一个重大的安全风险,但它确实有效。
from django.views.decorators.csrf import csrf_exempt
# Create your views here.
from django.http import HttpResponse
@csrf_exempt
def homePageView(request):
data = request.POST.get('data')
return HttpResponse(data)