Question

我收到此错误，我无法弄清楚如何修复：

Contextual type 'AnyObject' cannot be used with dictionary literal

我在互联网上搜索但未能找到答案。这是我的代码：

struct Sweet {

let key:String!
let content:String!
let addedByUser:String!
let itemReft:FIRDatabaseReference?

init (content:String, addedByUser:String, key:String = "") {
    self.key = key
    self.content = content
    self.addedByUser = addedByUser
    self.itemReft = nil
}

init (snapshot:FIRDataSnapshot) {
    key = snapshot.key
    itemReft = snapshot.ref

    if let dict = snapshot.value as? NSDictionary, let postContent = dict["content"] as? String {
        content = postContent
    } else {
        content = ""
    }

    if let dict = snapshot.value as? NSDictionary, let postUser = dict["addedByUser"] as? String {
        addedByUser = postUser
    } else {
        addedByUser = ""
    }

}

func toAnyObject() -> AnyObject {
    return ["content":content, "addedByUser":addedByUser]
}

错误发生在这一行：

return ["content":content, "addedByUser":addedByUser]

我一直在关注本教程iOS Swift Tutorial: Get started with Firebase and an App like Twitter

谢谢你的时间！

Answer 1

您必须将文字转换为所需类型

func toAnyObject() -> Any {
  return ["content":content, "addedByUser":addedByUser] as Any
}

但是 - 没有冒犯 - 将特定类型转换为更具特色的东西是愚蠢的。为什么不

func toDictionary() -> [String:String] {
  return ["content":content, "addedByUser":addedByUser]
}

Swift Firebase - 上下文类型＆＃39; AnyObject＆＃39;不能与字典文字一起使用

1 个答案: