Question

所以我在过去的一天半里一直坚持这个问题。我正试图在我的LWJGL游戏中实现2D可写文本框。文本框的渲染不是问题，并且完美无缺。

然而，我的意见并不是那么好。问题是我无法弄清楚如何检测单键按下，所以不是添加＆＃34; a＆＃34;对于我的输入字符串，它添加：＆＃34; aaaaaaaaaaaaaaaaaa＆＃34;，因为游戏时间非常快。

这是我的代码：

private boolean canType = false;

private static long curTime= System.currentTimeMillis();
private static long keyTypeTime = System.currentTimeMillis();
String input = "";

// Game loop
// I'm using a timer to limit typing, which doesn't work that well.

        if (curTime - keyTypeTime >= 100) {
            keyTypeTime = System.currentTimeMillis();
            canType = true;

        }

        if (canType) {
            char c = Keyboard.checkAllKeys();
            canType = false;
            if (c != '*') {
                if (c == '/') {
                    System.out.println("backspace");
                    if (input != null && input.length() > 0) {
                        input = input.substring(0, input.length() - 1);
                    }
                } else if (c == '{') {
                    storyLogic();
                } else {
                    input += c;
                }
            }
        }

这是我的实际键盘课程，以及＆＃34; checkAllKeys＆＃34;方法：

package me.mateo226.main;

import org.lwjgl.glfw.GLFWKeyCallback; import static org.lwjgl.glfw.GLFW。*;

public class Keyboard扩展了GLFWKeyCallback {

public static boolean[] keys = new boolean[65536];

// The GLFWKeyCallback class is an abstract method that
// can't be instantiated by itself and must instead be extended
// 
@Override
public void invoke(long window, int key, int scancode, int action, int mods) {
    // TODO Auto-generated method stub
    keys[key] = action != GLFW_RELEASE;
}

// boolean method that returns true if a given key
// is pressed.
public static boolean isKeyDown(int keycode) {
    return keys[keycode];
}

public static char checkAllKeys() {
    char key = '*';
    if(isKeyDown(GLFW_KEY_A)) {
        key = 'a';
    }
    if(isKeyDown(GLFW_KEY_Z)) {
        key = 'z';
    }
    if(isKeyDown(GLFW_KEY_SPACE)) {
        key = ' ';
    }
    if(isKeyDown(GLFW_KEY_BACKSPACE)) {
        key = '/';
    }
    if(isKeyDown(GLFW_KEY_ENTER)) {
        key = '{';
    }


    return key;

}

}

我还在学习LWJGL 3，所以键盘课不是我的，只有checkAllKeys方法由我制作。

谢谢！

Answer 1

string key2 = null;
public static char checkAllKeys() {
    char key = '*';
    if(isKeyDown(GLFW_KEY_A)) {
        key2 = 'a';
    }
    if(isKeyDown(GLFW_KEY_Z)) {
        key2 = 'z';
    }
    if(isKeyDown(GLFW_KEY_SPACE)) {
        key2 = ' ';
    }
    if(isKeyDown(GLFW_KEY_BACKSPACE)) {
        key2 = '/';
    }
    if(isKeyDown(GLFW_KEY_ENTER)) {
        key2 = '{';
    }

     if(!isKeyDown(GLFW_KEY_A)&&key2=='a') {
        key = 'a';
        key2 = null;
    }
    if(!isKeyDown(GLFW_KEY_Z)&&key2=='z') {
        key = 'z';
        key2 = null;
    }
    if(!isKeyDown(GLFW_KEY_SPACE)&&key2==' ') {
        key = ' ';
        key2 = null;
    }
    if(!isKeyDown(GLFW_KEY_BACKSPACE)&&key2=='/') {
        key = '/';
        key2 = null;
    }
    if(!isKeyDown(GLFW_KEY_ENTER)&&key2=='{') {
        key = '{';
        key2 = null;
    }
}

2D文本框的键盘输入

1 个答案: