Question

我对JavaScript很新。我需要两件事：

干掉我的代码。具体而言，{ leo }对象的 hasMoreOscarsThan 方法内部声明了许多变量。我需要在其他4种方法中以某种方式再次使用这些变量{ jenn }，{ sam }，{ mery }和{约翰}。

将这些变量声明为全局只是不起作用，因为我甚至不想在以后更改它们的值。

在其他对象的 hasMoreOscarsThan 方法中使用这些变量时，是否有任何方法可以干掉这些变量？

我有 getActorByName（） 功能。我无法在其中使用 toLowerCase（） 或 toUpperCase（） 函数。为什么？

如您所知，用户大多不会尝试写名称“Leonardo DiCaprio”，例如，大写字母和小写字母。 toLowerCase（） 会为我解决问题，但我无法让它发挥作用！为什么？

非常感谢您提前！

var actors = [
  leo = {
    name: 'Leonardo DiCaprio',
    age: 41,
    oscars: 1,
    hello: function() {
      var logActorName0 = console.log('Hello, my name is: ' + leo.name);


    // hasMoreOscarsThan - this method accepts one actor object as a parameter and
    //     returns true if the actor has more Oscars than the one that is passed as
    //     a parameter and false otherwise.


    },
    hasMoreOscarsThan: function(actorObj) {
      var leoName = actors[0].name;
      var jennName = actors[1].name;
      var samName = actors[2].name;
      var meryName = actors[3].name;
      var johnName = actors[4].name;
      var leoOscars = actors[0].oscars;
      var jennOscars = actors[1].oscars;
      var samOscars = actors[2].oscars;
      var meryOscars = actors[3].oscars;
      var johnOscars = actors[4].oscars;
      if (actorObj === leoName && leoOscars > leoOscars) {
        return true;
      } else if (actorObj === jennName && leoOscars > jennOscars) {
        return true;
      } else if (actorObj === samName && leoOscars > samOscars) {
        return true;
      } else if (actorObj === meryName && leoOscars > meryOscars) {
        return true;
      } else if (actorObj === johnName && leoOscars > johnOscars) {
        return true;
      } else if (actorObj !== leoName && actorObj !== jennName && actorObj !== samName && actorObj !== meryName && actorObj !== johnName) {
        var falseSearch = "Please enter a valid actor name!";
        return falseSearch;
      } else {
        return false;
      }
    }
  },
  jenn = {
    name: 'Jennifer Lawrence',
    age: 25,
    oscars: 1,
    hello: function() {
      var logActorName1 = console.log('Hello, my name is: ' + jenn.name);
    },
    hasMoreOscarsThan: function(actorObj) {
      console.log(leoname);
    }
  },

  sam = {
    name: 'Samuel L. Jackson',
    age: 67,
    oscars: 0,
    hello: function() {
      var logActorName2 = console.log('Hello, my name is: ' + sam.name);
    },
    hasMoreOscarsThan: function(actorObj) {

    }
  },
  mery = {
    name: 'Meryl Streep',
    age: 66,
    oscars: 3,
    hello: function() {
      var logActorName3 = console.log('Hello, my name is: ' + mery.name);
    },
    hasMoreOscarsThan: function(actorObj) {

    }
  },

  john = {
    name: 'John Cho',
    age: 43,
    oscars: 0,
    hello: function() {
      var logActorName4 = console.log('Hello, my name is: ' + john.name);
    },
    hasMoreOscarsThan: function(actorObj) {

    }
  },

  
function getActorByName(actor){
  var leoName = actors[0].name;
  var jennName = actors[1].name;
  var samName = actors[2].name;
  var meryName = actors[3].name;
  var johnName = actors[4].name;
    if (actor === leoName){
      return (leo);
    } else if (actor === jennName){
      return (jenn);
    } else if (actor === samName){
      return (sam);
    } else if (actor === meryName){
      return (mery);
    } else if (actor === johnName){
      return (john);
    } else if (actor !== leoName && actor !== jennName && actor !== samName && actor !== meryName && actor !== johnName){
      return "No Such An Actor Found!";
    }
};

<!doctype html>
<html>
<title>Actors</title>
<script src="script.js"></script>

</html>

Answer 1

我猜您使用单个filter操作执行此操作，如下所示;

＆＃13;

var hasMoreOscars = (o,a) => a.filter(e => e.oscarCount < o.oscarCount),
              arr = [{a:"leo",oscarCount:1},{a:"me",oscarCount:10},{a:"John", oscarCount: 3}, {a:"she",oscarCount:7}];

console.log(hasMoreOscars(arr[3],arr))

＆＃13;

Answer 2

你想要的只是一个简单的循环：

hasMoreOscarsThan: function (actorObj) {
    var myOscars = this.oscars;
    for (var i = 0; i < actors.length; i++) {
        var actorName = actors[i].name;
        if (actorName == actorObj) { // use toLowerCase() here if you want
            var actorOscars = actors[i].oscars;
            return actorOscars < myOscars;
        }
    }
    return "Please enter a valid actor name!";
}

有没有办法干掉这段代码？ +“toLowerCase（）”

2 个答案: