Question

如果年份的输入值= 2，我如何让我的程序在前12个月显示第1年，然后在接下来的12个月显示第2年？

另外，我不知道我的计算出错了。根据我想要的输出，总降雨量应该是37，但我得到39。

#the following are the values for input:
#year 1 month 1 THROUGH year 1 month 11 = 1
#year 1 month 12 THROUGH year 2 month 12 = 2

def main():
    #desired year = 2
    years = int(input("Enter the number of years you want the rainfall calculator to determine: "))
    calcRainFall(years)

def calcRainFall(yearsF):
    months = 12
    grandTotal = 0.0

    for years_rain in range(yearsF):
        total= 0.0
        for month in range(months):
            print('Enter the number of inches of rainfall for year 1 month', month + 1, end='')
            rain = int(input(': '))
            total += rain
        grandTotal += total
    #This is not giving me the total I need. output should be 37.
    #rainTotal = rain + grandTotal
    #print("The total amount of inches of rainfall for 2 year(s), is", rainTotal)
    print("The total amount of inches of rainfall for 2 year(s), is", grandTotal)
main()

Answer 1

在打印声明之前，您不需要为rainTotal再次添加降雨值。这是因为grandTotal每年都有降雨量。它已经两年加两次了。所以你所做的实际上是两次加雨的最后一次（在这种情况下为2）制作你的打印声明并删除rainTotal -

print("The total amount of inches of rainfall for 2 year(s), is", grandTotal)

Answer 2

我已经缩短了你的代码。希望这是一个完整而正确的计划：

def main():
    years = int(input("Enter the number of years you want the rainfall calculator to determine: "))
    calcRainFall(years)

def calcRainFall(yearsF):
    months = 12 * yearsF # total number of months
    grandTotal = 0.0     # inches of rain

    for month in range(months):
        # int(month / 12): rounds down to the nearest integer. Add 1 to start from year 1, not year 0.
        # month % 12: finds the remainder when divided by 12. Add 1 to start from month 1, not month 0.
        print('Enter the number of inches of rainfall for year', int(month / 12) + 1, 'month', month % 12 + 1, end='')
        rain = int(input(': '))
        grandTotal += rain
    print("The total amount of inches of rainfall for", yearsF, "year(s), is", grandTotal)

main()

Answer 3

rainTotal = rain + grandTotal

正在执行以下操作：2 + 37，因为您的最后一次降雨输入= 2且已经是总数或者总计= 37（每年的总输入数），因此 rainTotal = rain + grandTotal 是不需要

Answer 4

您的代码备注：

如前所述，rainTotal是不必要的。

您可以尝试：

print 'Enter the number of inches of rainfall for year %d month %d' % (years_rain, month), end='')

这将填充第一个％d表示years_rain的值，第二个％d表示月份值作为for循环运行。

此技巧也可用于最终打印行，如下所示：

print("The total amount of inches of rainfall for %d year(s) % yearsF, is", grandTotal)

嵌套循环计算输出不正确，但程序运行

4 个答案: