Question

我需要打开弹出窗口＆＃34; Page1.html＆＃34;然后自动点击按钮＆＃34; VOTE＆＃34;然后将该页面重定向到＆＃34; Page2.html＆＃34;。

我知道以下用于打开弹出窗口的代码＆＃34; Page1.html＆＃34;

<script type="text/javascript">
function makeNewWindow()
{
winchlildren = window.open("./page1.html","winchlildren","height=600,width=85")
}
</script>

我有按钮所在的表单。

<!DOCTYPE html>
<html>
<head></head>
<body>
<div class="votelog_info">
    <div class="votelog_nav">
        <div class="vote_nav is_voteing">
            <form method="post">
            <input type="hidden" name="form_pass" value="form_pass_qk9telqr2G4hU" />
            <input type="hidden" name="id" value="norrcon" />
            <button type="submit" class="vote for" name="submit">Vote</button></form>
        </div>
    </div>
</div>
</body>
</html>

按下此按钮后，我希望将该页面重定向到＆＃34; Page2.html＆＃34;
我希望这个过程在后台和全屏尺寸下完成谢谢！
埃德加。

Answer 1

正如您已将此问题提交给Jquery，您可以使用JS完成它：

<script type="text/javascript">
    function makeNewWindow() {
        winchlildren = window.open("./page1.html","winchlildren","height=600,width=85");

        $('.is_voteing input[name="submit"]').click();
    }
    $(".is_voteing input[name="submit"]').click(function(){
        // do voting functionality when button is clicked
        // AJAX is preffered, if process to be done in the background
        . . .
        //Redirect completely to page2.html (full screen size, as you reffered)
        window.location = "./page2.html";
    });
</script>

然后在页面上的任何事件上调用makeNewWindow()。

JavaScript打开弹出窗口并模拟鼠标单击特定位置

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