Question

我的sql查询存在一些问题，这个问题过去常常会得到一个结合了所有城镇的玩家的流行音乐总数但由于某种原因它会给出错误的总流行音乐我也被告知使用绑定参数，但我不确定它们是什么以及如何使用它们。任何帮助都会非常感谢你。

<!DOCTYPE html>
<html>
<head>
<style>
table {
    width: 100%;
    border-collapse: collapse;
}

table, td, th {
    border: 1px solid black;
    padding: 5px;
}

th {text-align: left;}
</style>
</head>
<body>

<?php
$q = intval($_GET['q']);
$latitude = -838;
$longitude = -493;
$con = mysqli_connect('localhost','User','Password','Database');
if (!$con) {
    die('Could not connect: ' . mysqli_error($con));
}

mysqli_select_db($con,"Database");
$sql="SELECT towns.location_x,  towns.location_y,  players.*, 
            town_deltas.*, town_deltas.town_id, 
            sum( town_deltas.population ) as total_population  
      FROM `town_deltas` 
        LEFT JOIN players ON town_deltas.owner_id = players.player_id 
        LEFT JOIN towns ON town_deltas.town_id = towns.town_id 
      WHERE town_deltas.owner_id = '".$q."' 
      GROUP BY owner_id, data_timestamp 
      ORDER BY `town_deltas`.`town_id` ASC, 
               `town_deltas`.`data_timestamp` ASC";



$result = mysqli_query($con,$sql); 
echo "<table>
<tr>

<th>data_timestamp</th>

<th>name</th>


<td>population</td>
<td>location_x</td>
<td>location_y</td>
<td>distance</td>
</tr>";
while($row = mysqli_fetch_array($result)) {
    echo "<tr>";


    echo "<td>" . $row['data_timestamp'] . "</td>";

    echo "<td>" . $row['Player_name'] . "</td>";


    echo "<td>" . $row['total_population'] . "</td>";

    echo "<td>" . $row['location_x'] . "</td>";
    echo "<td>" . $row['location_y'] . "</td>";
    echo "<td>" . $row['distance'] . "</td>";

    echo "</tr>";
}

echo "</table>";
mysqli_close($con);
?>
</body>
</html>

破了总弹出页面

data_timestamp      name         population
2016-09-25 00:03:29 Kodabear    50315100

应该显示什么

data_timestamp       name    population
2016-09-25 00:03:29 Kodabear  335,434

玩家表

player_id   race_id alliance_id alliance_role_id    Player_name 
237186        1     78           381                 Kodabear

town_deltas表

5198444 2016-09-21 00:03:47 282609  237186  01 Smokey The Bear  29634   0 0
5198445 2016-09-21 00:03:47 289820  237186  02 Littlebears  28557   0   0   
5198446 2016-09-21 00:03:47 292694  237186  03 Panda-bear   28068   0   0
5198447 2016-09-21 00:03:47 296040  237186  04 Humphrey 29420   1   1
5198448 2016-09-21 00:03:47 296593  237186  05 Winnie-the-Pooh  29527   0   0
5198449 2016-09-21 00:03:47 296914  237186  06 Shayna The Bear  29287   0   0
5198450 2016-09-21 00:03:47 301887  237186  07 Basil the Bear   27684   0   0
5198451 2016-09-21 00:03:47 316315  237186  08 Gummybear    27546   0   0
5198452 2016-09-21 00:03:47 350576  237186  09 Paddington   28919   0   0
5198453 2016-09-21 00:03:47 365385  237186  10 Walkingbear  26369   0   0
5198454 2016-09-21 00:03:47 377604  237186  11 PanserbjÃ¸rne    25636   0   0
5198455 2016-09-21 00:03:47 404089  237186  12 YogiBear 19672   0   0
5198456 2016-09-21 00:03:47 405583  237186  13 Baloo    3938    0   0

Answer 1

城镇人口将一再重复。你不想要sum()。只需采用max()：

SELECT towns.location_x,  towns.location_y,  players.*, 
       town_deltas.*, town_deltas.town_id, 
       max( town_deltas.population ) as total_population

您的查询还有很多其他问题 - 尤其是SELECT中未正确汇总的列。但是，这可能会解决您的直接问题。

sql查询显示错误的总pop

1 个答案: