我收到错误“HTTP Status 404- / servlet / FormPost 类型状态报告 message / servlet / FormPost description请求的资源不可用 Apache Tomcat / 7.0.72“
任何人都可以看到我的代码有什么问题吗?我正在使用Eclipse和Tomcat v7.0。 我正在尝试让程序输出一个表单,写入随机访问文件,并从随机访问文件返回结果。我是一名SQL程序员,不是Java servlet的粉丝,也不是很了解它们。请解释好像我是编程新手,或编辑我的代码。谢谢!
这是我的代码:
package net.codejava;
import java.io.*;
import javax.servlet.*;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;
@WebServlet(name="FormPost", urlPatterns={"/FormPost"})
public class FormPost extends HttpServlet {
private static final long serialVersionUID = 1L;
private String target = "localhost:7070";
public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException, ServletException{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
printHeader(out);
printForm(out);
printFooter(out);
}
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
final int BUFFER_LENGTH = 41;
String data = null;
PrintWriter out = response.getWriter();
RandomAccessFile randomAccessFile = new RandomAccessFile("C:/temp/week4.dat", "rw");
StringBuffer buffer = new StringBuffer(request.getParameter("myName"));
StringBuffer buffer2 = new StringBuffer(request.getParameter("myAddress"));
StringBuffer buffer3 = new StringBuffer(request.getParameter("myCityAndState"));
randomAccessFile.seek(randomAccessFile.length());
randomAccessFile.writeBytes(buffer.toString());
randomAccessFile.seek(0);
printForm(out);
buffer.setLength(BUFFER_LENGTH);
buffer.setCharAt(BUFFER_LENGTH - 1, '\n');
randomAccessFile.seek(randomAccessFile.length());
randomAccessFile.writeChars(buffer.toString());
randomAccessFile.writeChars(buffer2.toString());
randomAccessFile.writeChars(buffer3.toString());
randomAccessFile.seek(0);
while ((data = randomAccessFile.readLine()) != null){
out.println(data + "<br />");
randomAccessFile.close();
doPost(request, response);
}
printFooter(out);
}
public void printHeader(PrintWriter out){
out.println("<!DOCTYPE html>");
out.println("<html lang='en'>");
out.println("<title>");
out.println("Servlet Read Write File");
out.println("</title>");
out.println("<body>");
out.println("<div>");
}
public void printFooter(PrintWriter out){
out.println("</div>");
out.println("</body>");
out.println("</html>");
}
public void printForm(PrintWriter out){
out.println("<form method='post' action='http://" + target + "/MyServlet/FormPost'>");
out.println("<label>Enter Name</label> ");
out.println("<input type='text' name='myName' size='30' maxlength='30'/>");
out.println("<input type='submit' />");
out.println("<label>Enter Address</label> ");
out.println("<input type='text' name='myAddress' size='30' maxlength='30'/>");
out.println("<input type='submit' />");
out.println("<label>Enter City and State</label> ");
out.println("<input type='text' name='myCityAndState' size='30' maxlength='30'/>");
out.println("<input type='submit' />");
out.println("</form>");
}
}
答案 0 :(得分:1)
问题与您的方法实施无关
HTTP 404告诉您tomcat http-server找不到您的请求的任何处理程序。
在简单的情况下,您的请求应该是"localhost:8080/<your_war_file_/_app_name>/<string_matching_your_web_servlet_pattern>"