Question

我有一个看起来像这样的json文件：

[["{\"id\":1474721566304,\"name\":\"GGG\",\"brand\":\"GG\",\"price\":\"3\"}"],["{\"id\":1474721570904,\"name\":\"GGGH\",\"brand\":\"GGH\",\"price\":\"4\"}"],["{\"id\":1474721574188,\"name\":\"GGGH\",\"brand\":\"GGHH\",\"price\":\"5\"}"]]

我要做的是从它id删除它的记录。为此，我有以下PHP代码：

<?php
$string = file_get_contents("products.json");
$json_a = json_decode($string, true); //turning JSON-string into an array containing JSON-strings

$arr = array();
foreach ($json_a as $key) {
    array_push($arr,json_decode($key[0],true)); //and here you turning each of the JSON-strings into objects themselves


}
$data= $_GET['data'];
$i=0;
foreach($arr as $element) {
   if($data == $element["id"]){
      unset($arr[$i]);//removing the product by ID
   }
   $i++;
}

var_dump($arr);
$arr2 = array();

foreach ($arr as $key) {//trying to make it look like the original json.
   array_push($arr2,json_decode($key[0],true));
}
//var_dump($arr2);
echo json_encode($arr2);
?>

我从这段代码得到的是：

array(2) { [0]=> array(4) { ["id"]=> float(1474721566304) ["name"]=> string(3) "GGG" ["brand"]=> string(2) "GG" ["price"]=> string(1) "3" } [1]=> array(4) { ["id"]=> float(1474721570904) ["name"]=> string(4) "GGGH" ["brand"]=> string(3) "GGH" ["price"]=> string(1) "4" } }

我真的没有想法如何使这个数组看起来像我在这篇文章中首先显示的原始JSON。我尝试了很多不同的东西，但我无法让它发挥作用。我的想法是在用它的ID删除记录之后将旧JSON替换为我想在这里构建的新JSON。

我是php新手，我很感激我的问题。

Answer 1

首先 - 您输入的JSON错误：

array (size=3)
  0 => 
    array (size=1)
      0 => string '{"id":1474721566304,"name":"GGG","brand":"GG","price":"3"}' (length=58)
  1 => 
    array (size=1)
      0 => string '{"id":1474721570904,"name":"GGGH","brand":"GGH","price":"4"}' (length=60)
  2 => 
    array (size=1)
      0 => string '{"id":1474721574188,"name":"GGGH","brand":"GGHH","price":"5"}' (length=61)

您没有'id'，也没有'name'，'GGG'和其他键。你只有一个长串。您应该删除不必要的引号。之后你的JSON应该是这样的：

[[{"id":1474721566304,"name":"GGG","brand":"GG","price":"3"}],[{"id":1474721570904,"name":"GGGH","brand":"GGH","price":"4"}],[{"id":1474721574188,"name":"GGGH","brand":"GGHH","price":"5"}]]

最后，您的PHP代码可以更短：

$json = "[[{\"id\":1474721566304,\"name\":\"GGG\",\"brand\":\"GG\",\"price\":\"3\"}],[{\"id\":1474721570904,\"name\":\"GGGH\",\"brand\":\"GGH\",\"price\":\"4\"}],[{\"id\":1474721574188,\"name\":\"GGGH\",\"brand\":\"GGHH\",\"price\":\"5\"}]]";
$input = json_decode($json, true);
$output = array();
foreach($input as $element) { //you don't need to declare yet another array, just use the one you already have
    if($_GET['data'] != $element[0]["id"]){ //and not unset, just add to new array if you want
       $output[] = $element; //shorter and faster than array_push()
    }
}
echo json_encode($output);

Answer 2

试试这段代码：

$string = file_get_contents("product.json");
$json_a = json_decode($string, true); //turning JSON-string into an array containing JSON-strings

$arr = array();
foreach ($json_a as $key) {
    array_push($arr,json_decode($key[0],true)); //and here you turning each of the JSON-strings into objects themselves
}
$data= 0;
$i=0;
foreach($arr as $element) {
   if($data == $element["id"]){
      unset($arr[$i]);//removing the product by ID
   }
   $i++;
}

// print_r($arr);
$arr2 = array();
foreach($arr as $key => $val) {
    $arr2[][] = $val;
}
//var_dump($arr2);
echo json_encode($arr2);

使用PHP

2 个答案: