此代码我习惯于根据需要进行文本更改。
private void textBox1_TextChanged(object sender, EventArgs e)
{
string A = textBox1.Text.Trim();
A = A.Replace("A", "C");
A = A.Replace("F", "H");
A = A.Replace("C", "W");
A = A.Replace("B", "G");
textBox2.Text = (A);
}
现在我需要停止文本更改, 如果我输入' |'在tetxbox1中的符号,我需要 如果我输入' |'再次符号,例如此图像中发生的事情。
那么我怎样才能防止这两个符号之间的文本发生变化||
答案 0 :(得分:1)
您需要更换无法工作的代码,因为它会不断更改相同字符串的字符(您将A更改为C,稍后将C更改为W,所以你最后的第一个角色是W而不是你想要的C。
下面是一个过于复杂的方法(我还添加了一个方法,它贯穿执行替换的字符串的每个字符),但它应该可以工作,并且您可以根据需要进行更改。祝你好运
private void textBox1_TextChanged(object sender, EventArgs e)
{
string A = textBox1.Text.Trim();
string[] Aarry = A.Split('|');
string cleanedString = "";
for (int i = 0; i < Aarry.Length; i++)
{
if (i % 2 == 0)
cleanedString += FixText(Aarry[i]) + " ";
else
cleanedString += Aarry[i] + " ";
}
textBox2.Text = cleanedString ;
下面的方法将遍历每个执行替换的角色
public string FixText(string A)
{
string newText = "";
for (int i = 0; i < A.Length; i++)
{
switch (A.Substring(i, 1))
{
case "A":
newText += A.Substring(i, 1).Replace("A", "C");
break;
case "F":
newText += A.Substring(i, 1).Replace("F", "H");
break;
case "C":
newText += A.Substring(i, 1).Replace("C", "W");
break;
case "B":
newText += A.Substring(i, 1).Replace("B", "G");
break;
default:
break;
}
}
return newText;
}
要处理您拥有的&gt; 500行替换类型,您可以使用以下方法设置字典:
public Dictionary<string, string> ReturnReplacementDictionary()
{
Dictionary<string, string> dictLibrary = new Dictionary<string,string)()
{
{"A","C"},
{"F","H"},
{"C","W"},
{"B","G"}
};
return dictLibrary;
}
在上文中,您只需继续添加所有其他替换值。
然后你会调用下面的方法而不是switch case(如果你没有在字典方法中添加字符/替换,你可以看到它只是将替换字符设置为空白):
public string FixTextUsingDictionary(string A)
{
Dictionary<string, string> replaceDict = ReturnReplacementDictionary();
string newText = "";
for (int i = 0; i < A.Length; i++)
{
string replacementLetter="";
if (replaceDict.TryGetValue(A.Substring(i, 1), out replacementLetter))
{
newText += replacementLetter;
}
// Added so that if the char is not in the dictionary the output will just have the original char
else { newText += A.Substring(i, 1); }
}
return newText;
}
祝你好运
答案 1 :(得分:1)
如果手动输入文本而不是从剪贴板粘贴,我的解决方案将是:
int counter = 0;
private string replaceSpecial(string A)
{
if (A.Equals("A")) return "C";
else if (A.Equals("F")) return "H";
else if (A.Equals("C")) return "W";
else if (A.Equals("B")) return "G";
else if (A.Equals("|")) return "";
else return A;
}
private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
if (e.KeyChar.Equals('|'))
{
counter++;
}
if (counter == 0 || counter % 2 == 0)
textBox2.Text += replaceSpecial(e.KeyChar.ToString());
else
textBox2.Text += e.KeyChar.ToString().Replace("|", "");
}
考虑到唯一输入的字符是“|”。 祝你好运
答案 2 :(得分:0)
void StringReplace(string initialString)
{
bool insideSpecialCharacter = false;
string[] Pattern = { "A-C", "C-W", "F-H", "B-G" };
string specialCharacter = "|";
char[] characters = initialString.ToCharArray();
char?[] Newcharacters = new char?[characters.Length];
for (int i = 0; i < characters.Length; i++)
{
if (!characters[i].ToString().Equals(specialCharacter))
{
if (insideSpecialCharacter)
{
Newcharacters[i] = characters[i];
}
else
{
CheckPattern(Pattern, characters, Newcharacters, i);
}
}
else
{
insideSpecialCharacter = (insideSpecialCharacter) ? false : true;
}
}
txtSecond.Text = string.Concat(Newcharacters).Trim();
}
//-------Checks the Pattern Array and Replaces the Characters-----------
private static void CheckPattern(string[] Pattern, char[] characters, char?[] Newcharacters, int i)
{
for (int j = 0; j < Pattern.Length; j++)
{
string[] replaceValue = Pattern[j].Split('-');
if (characters[i].ToString() == replaceValue[0])
{
Newcharacters[i] = Convert.ToChar(characters[i].ToString().Replace(characters[i].ToString(), replaceValue[1]));
break;
}
else
{
Newcharacters[i] = characters[i];
}
}
}