Question

我正在xamarin中构建一个应用程序，我试图从另一个对话框中弹出AleartDialog并且它成功发生但问题是：

当第二个对话框打开时，前一个对话框变得不可见，当我返回时，它会自动弹出。

下图可以使要求更加清晰

图像1是我想要的，但它就像图像2和图像3

下面的

是我的DialogInterface类

 public class DialogBuilder : DialogFragment {

    public static DialogBuilder NewInstance(bool showPrimary) {
        DialogBuilder fragment = new DialogBuilder { Arguments = new Bundle() };
        fragment.Arguments.PutBoolean("boolean", showPrimary);
        return fragment;
    }
    public override void OnCreate(Bundle savedInstanceState) {
        base.OnCreate(savedInstanceState);

        // Create your fragment here
    }

    public override View OnCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        // Use this to return your custom view for this Fragment
       // bool showPrimaryLayout = Arguments.GetBoolean("boolean");
        View view = null;
        bool showPrimaryLayout = Arguments.GetBoolean("boolean");
        InputMethodManager inputManager = (InputMethodManager)Activity.GetSystemService(Context.InputMethodService);
        var currentFocus = Activity.CurrentFocus;
        if (currentFocus != null) {
            inputManager.HideSoftInputFromWindow(currentFocus.WindowToken, HideSoftInputFlags.none);
        }
        if (showPrimaryLayout) {
            view = inflater.Inflate(Resource.Layout.dialog_edit_schedule_party, container, false);

            var button_add_hostess = view.FindViewById<Button>(Resource.Id.btn_add_hostess);
            button_add_hostess.Click += (s, e) => ShowDialog(false);
        }
        else {
            view = inflater.Inflate(Resource.Layout.fragment_add_hostess_dialog, container, false);
        }

        return view;
    }
    public void ShowDialog(bool isPrimary) {

        FragmentTransaction transction = FragmentManager.BeginTransaction();
        //Remove fragment else it will crash as it is already added to backstack
        Fragment prev = FragmentManager.FindFragmentByTag("dialog");
        if (prev != null) {
            transction.Remove(prev);
        }

        transction.AddToBackStack(null);
        DialogBuilder builder = NewInstance(isPrimary);
        builder.Show(transction, "dialog");
    }

}

}

在我的活动类中实现

private void popUpDialog() {
        FragmentTransaction ft = FragmentManager.BeginTransaction();
        //Remove fragment else it will crash as it is already added to backstack
        Fragment prev = FragmentManager.FindFragmentByTag("dialog");
        if (prev != null) {
            ft.Remove(prev);
        }

        ft.AddToBackStack(null);

        // Create and show the dialog.
        DialogBuilder dialog = DialogBuilder.NewInstance(true);
        dialog.Cancelable = false; 
        //Add fragment
        dialog.Show(ft, "dialog");
    }

感谢任何帮助。

Answer 1

问题在于以下代码

convert $(gls -v "$file"*.jpeg) "$file".pdf

对于这两个对话框，发送的字符串标签是相同的，这导致隐藏了之前打开的对话框。

解决方案：

dialog.Show（ft，“dialog_one”）; //第一个对话框。

dialog.Show（ft，“dialog_two”）; //第二个

Xamarin.Android：在尝试打开另一个警报对话框时隐藏了AlertDialog

1 个答案: