我想从ASP.NET MVC Controller中的URL获取ID并将其插入到Project_ID中,下面是我的代码,我试过但它现在正在为我工作。
http://localhost:20487/ProjectComponent/Index/1
我的控制器
[HttpPost]
public JsonResult SaveComponent(OrderVM O, int id)
{
bool status = false;
if (ModelState.IsValid)
{
using (Entities db = new Entities())
{
ProjComponent ProjComponent = new ProjComponent { project_id = id, title = O.title, description = O.description };
foreach (var i in O.ProjComponentActivities)
{
ProjComponent.ProjComponentActivity.Add(i);
}
db.ProjComponents.Add(ProjComponent);
db.SaveChanges();
status = true;
}
}
}
答案 0 :(得分:0)
你可以随时使用隐藏字段并通过jquery / javscript更新它并将其发送到ajax帮助器的后端.....
确保1.name应该是ActionMethod param和3.Jquery,jQuery Validate和jQuery unobstrusive ajax正确加载的名称
我的代码.cshtml
<script src="~/Scripts/jquery-2.1.4.min.js"></script>
<script src="~/Scripts/jquery.validate.min.js"></script>
<script src="~/Scripts/jquery.validate.unobtrusive.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>
<div>
@{
AjaxOptions options = new AjaxOptions();
options.HttpMethod = "POST";
options.OnBegin = "OnBeginRequest";
options.OnSuccess = "OnSuccessRequest";
options.OnComplete = "OnCompleteRequest";
options.OnFailure = "OnFailureRequest";
// options.Confirm = "Do you want to Add Country ?";
options.UpdateTargetId = "divResponse";
options.InsertionMode = InsertionMode.InsertAfter;
}
@using (Ajax.BeginForm("AjaxSend", "Stackoverflow", options))
{
<input type="hidden" name="project_id" id="project_id" value="project_id" />
<input type="submit" value="Click me" />
}
</div>
<div id="divResponse">
</div>
<script>
$(function() {
var url = window.location.href;
var array = url.split('/');
var lastsegment = array[array.length - 1];
console.log(lastsegment);
$('#project_id').val(lastsegment);
});
function OnBeginRequest() {
console.log('On Begin');
}
function OnCompleteRequest() {
console.log('On Completed');
}
function OnSuccessRequest() {
console.log('On Success');
}
function OnFailureRequest() {
console.log('On Failure');
}
</script>
和控制器
[HttpPost]
public JsonResult AjaxSend(String project_id)
{
//rest goes here
return Json(new { Success = true });
}
此链接可能会有所帮助link
答案 1 :(得分:0)
您可以像这样从URL获取ID:
工资单:
html = $(data).find('.product-quantity-details .quantity');
查看:
public ActionResult Index(int id)
{
ViewBag.ID = id;
Your Code......
return View(...);
}
} 现在,您在变量中有了一个ID