Question

我只想删除列表的最大和最小副本数字。示例：（ 1 1 1 4 4 5 6 8 8 8 ）结果：（ 1 4 4 5 6 的 8 ）

如何将max（）min（）函数与list(set(x))组合？

还是有另一种方式吗？

s = raw_input("Please Input a series of numbers")
numbers = map(int, s.split())

numbers.remove(max(numbers))
numbers.remove(min(numbers))
average = sum(numbers)/float(len(numbers))
print average

Answer 1

s = raw_input("Please Input a series of numbers")
numbers = map(int, s.split())
# numbers = [1, 1, 1, 4, 4, 5, 6, 8, 8, 8]
mi = min(numbers)
ma = max(numbers)
b = [mi] + [x for x in numbers if x != mi and x != ma] + [ma]

Answer 2

以下是使用某些itertools函数解决问题的一般方法。该解决方案会将重复的最小值和最大值重叠为单个值，只要重复出现在哪里：

from itertools import groupby,starmap,chain
#first we count the sequence length for each group of number in the list
c=[[number,len(list(seq))] for number,seq in groupby(numbers)]
print(c)

#we collapse the repetitions only for min and max
for group in c:
    if group[0] == min(numbers) or group[0]== max(numbers):
        group[1]=1       
print(c)

#we put back the list together
numbers=list(chain(*starmap(lambda x,n : [x]*n, c)))
print(numbers)

示例输出：

>>>numbers=[1,1,1,4,4,5,6,8,8,8]
[1, 4, 4, 5, 6, 8]
>>>numbers=[4,4,1,1,1,5,6,8,8,8]
[4, 4, 1, 5, 6, 8]
#edge case if there are multiple groups of min :
>>>numbers=[4,4,1,1,1,5,1,1,1,6,8,8,8]
[4, 4, 1, 5, 1, 6, 8]

删除数字列表的最大和最小重复

2 个答案: