Pentaho CSV文件输入步骤 - 附件中的逗号分隔符

Question

Pentaho 6.1 CSV文件输入步骤我有个奇怪的问题。

我在CSV文件中有以下值：

  

“2016年9月16日”， “测试”， “”， “测试”，“检验，   SL”， “[测试]”， “测试”，39.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000 ，0.000000

我在CSV文件中使用输入步骤：

Delimiter: ,
Enclosure: "

预览选项工作正常，但当我尝试将该内容导入数据库表并执行转换时，我收到以下错误：

  

2016/09/23 22:04:46 - 写到log.0 - 2016/09/23 22:04:46 - 写到   log.0 - 2016/09/23 22:04:46 - 写入log.0 - at   org.pentaho.di.core.row.value.ValueMetaBase.convertStringToNumber（ValueMetaBase.java:803）   2016/09/23 22:04:46 - 写入log.0 - at   org.pentaho.di.core.row.value.ValueMetaBase.getNumber（ValueMetaBase.java:1631）   2016/09/23 22:04:46 - 写入log.0 - ... 7更多2016/09/23 22:04:46    - 写入log.0 - 引起：org.pentaho.di.core.exception.KettleValueException：2016/09/23   22:04:46 - 写入log.0 - 请求字符串：无法转换字符串   to number：在位置1找到值的非数字字符   [SL”， “[测试]”， “测试”，38.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000,0.000000， 0.000000,0.000000

我认为它存在以下值“test，S.L”的问题。 （第5栏）。我不明白为什么因为预览选项有效。

Answer 1

我尝试了你的输入集，不管你信不信，我对嵌入式逗号没有任何问题。似乎问题是转换数字字段。我将它们设置为Number数据类型并使用蒙版进行摆弄，但唯一能使其工作的是指定修剪类型“左”。当我这样做时，一切都很好。