在vertica中有一个表:像这样测试:
class Country(models.Model):
name = models.CharField(max_lenght=200)
我如何使用聚合函数或如何编写查询来获取这样的数据(vertica语法)?
ID | name
1 | AA
2 | AB
2 | AC
3 | AD
3 | AE
3 | AF
答案 0 :(得分:2)
首先,您需要为agg_concatenate
编译udx。
-- Shell commands
cd /opt/vertica/sdk/examples/AggregateFunctions/
g++ -D HAVE_LONG_INT_64 -I /opt/vertica/sdk/include -Wall -shared -Wno-unused-value -fPIC -o Concatenate.so Concatenate.cpp /opt/vertica/sdk/include/Vertica.cpp
-- vsql commands
CREATE LIBRARY AggregateFunctionsConcatenate AS '/opt/vertica/sdk/examples/AggregateFunctions/Concatenate.so';
CREATE AGGREGATE FUNCTION agg_concatenate AS LANGUAGE 'C++' NAME 'ConcatenateFactory' LIBRARY AggregateFunctionsConcatenate;
然后你可以进行如下查询:
select id, rtrim(agg_concatenate(name || ', '),', ') ag
from mytable
group by 1
order by 1
使用rtrim摆脱最后的','。
如果您需要以某种方式对聚合进行排序,则可能需要在内联视图中选择/排序或使用first。
答案 1 :(得分:1)
SELECT id,
MAX(DECODE(row_number, 1, a.name)) ||
NVL(MAX(DECODE(row_number, 2, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 3, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 4, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 5, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 6, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 7, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 8, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 9, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 10, ',' || a.name)), '')||
NVL(MAX(DECODE(row_number, 11, ',' || a.name)), '') ||
NVL(MAX(DECODE(row_number, 12, ',' || a.name)), '') ag
FROM
(SELECT id, name, ROW_NUMBER() OVER(PARTITION BY name ORDER BY id) row_number FROM test) a
GROUP BY a.id
ORDER BY a.id;
答案 2 :(得分:1)
另一种方法是使用strings package on github中的GROUP_CONCAT
。
select id, group_concat(name) over (partition by id order by name) ag
from mytable
然而,此方法存在一些限制,因为分析udx不允许您包含其他聚合(并且您必须内联它或使用它来向其添加更多数据)。