通过post方法向PHP发送空

时间:2016-09-23 16:47:26

标签: php android

我正在使用Android项目,我需要使用PHP连接MySQL。为此,我使用PHP post方法将数据从Android传递到PHP。我的代码如下:

HttpURLConnection httpURLConnection= (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
httpURLConnection.setDoInput(true);
OutputStream outputStream=httpURLConnection.getOutputStream();

BufferedWriter bufferedWriter=new BufferedWriter(new OutputStreamWriter(outputStream,"UTF-8"));
String post_data=URLEncoder.encode("mobile","UTF-8")+"="+URLEncoder.encode(mobile,"UTF-8")+"&"+
URLEncoder.encode("password","UTF-8")+"="+URLEncoder.encode(password,"UTF-8");
bufferedWriter.write(post_data);
// Toast.makeText(context,"after data pass",Toast.LENGTH_LONG).show();
bufferedWriter.flush();
bufferedWriter.close();

InputStream inputStream=httpURLConnection.getInputStream();
BufferedReader bufferedReader=new BufferedReader(new InputStreamReader(inputStream,"iso-8859-1"));
String result="";
String line="";
while((line=bufferedReader.readLine())!=null){
    result += line;
}
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
return  result;

但问题出在PHP脚本中。没有数据通过,而PHP脚本收到一个空字符串。为什么会这样?那应该是什么解决方案? 我的PHP代码是:

<?php 
require "conn1.php"; 
$mobile= $_POST["mobile"]; 
$user_password= $_POST["password"]; 
$query="select * from pharmacytable where mobile like '$mobile' and PharPassword like '$user_password';"; 
$result=mysqli_query($conn, $query); 
if(mysqli_num_rows($result)>0){ 
    echo "Login success"; 
} else{ 
    echo "Login failed"; 
} 
?>

0 个答案:

没有答案