Question

我有桌子从json得到一些东西我选择行的索引我要打开其他控件和其他控件获得第一个varbiles 想象代码但是在代码中尝试从tableview发送到seque但是在seque中没有任何代码发生错误我想从桌子上拿到网址

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath:
    IndexPath)
{

  // let selectedEpisode = self.episodes[(indexPath as NSIndexPath).row]


    self.performSegue(withIdentifier: "videoplay", sender: indexPath);

}
override func tableView(_ tableView: UITableView, willDisplay cell: UITableViewCell, forRowAt indexPath: IndexPath) {

    cell.alpha = 0
    let transform = CATransform3DTranslate(CATransform3DIdentity, -250, 20, 0)
    cell.layer.transform = transform
    UIView.animate(withDuration: 1.0) {
        cell.layer.transform = CATransform3DIdentity
        cell.alpha = 1
    }
}
func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

    if segue.identifier == "videoplay" {
        if let indexPath = self.tableView.indexPathForSelectedRow {
           let selectedEpisode = self.episodes[(indexPath as NSIndexPath).row]
           let yosrihh = selectedEpisode.url! as URL
           let destination = segue.destination as! videoPlayViewController

            destination.urll = yosrihh
        }
    }
}

Answer 1

问题在于，在Swift 3 prepareForSegue(:sender:)中更改为prepare(for:sender:)，因此只需更改此方法，然后全部设置为。

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    //Your code
}

从tableview发送didselect to seque发送其他控制器

1 个答案: