我有一个data.frame有两个组和两个变量（组变量除外），例如：
set.seed(1729)
temp <- data.frame(group=c(1,2),value1=rnorm(12),value2=rnorm(12))
temp = temp[order(temp$group),]
# group value1 value2
# 1 0.21531616 0.08679615
# 1 1.08604925 0.36344973
# 1 1.04225410 0.53281840
# 1 -1.40843189 0.52096971
# 1 -0.07130541 -0.47550518
# 1 0.18839979 1.96241245
# 2 0.18374784 -0.64102941
# 2 0.02871298 -0.67746579
# 2 0.08826553 -0.32679060
# 2 0.05522136 -0.31371224
# 2 0.36086719 -0.10004339
# 2 -0.55618926 1.22760816
我计算了temp $ value1＆amp;的分位数。温度$ VALUE2
qt1 = quantile(temp$value1,probs = c(0.25,0.5,0.75))
qt2 = quantile(temp$value2,probs = c(0.25,0.5,0.75))
对于每个小组，我需要 （1）temp $ value1的值的数量＆lt; qt1 [1]（2）temp $ value1的值的数量＆lt; qt [2]（3）temp $ value1的值的数量＆lt; QT1 [3]。同样，temp $ value2的计数有六个值（两组和三个分位数）。
作为代码，它是（我手动将每个组+变量复制到一个向量中以说明我想要的东西）
g1v1=c(0.21531616,1.08604925,1.04225410,-1.40843189,-0.07130541,0.18839979)
length(g1v1[g1v1<qt1[1]])
length(g1v1[g1v1<qt1[2]])
length(g1v1[g1v1<qt1[3]])
g2v1=c(0.18374784,0.02871298,0.08826553,0.05522136,0.36086719,-0.55618926)
length(g1v2[g1v2<qt1[1]])
length(g1v2[g1v2<qt1[2]])
length(g1v2[g1v2<qt1[3]])
g1v2=c(0.08679615,0.36344973,0.53281840,0.52096971,-0.47550518,1.96241245)
length(g2v1[g2v1<qt2[1]])
length(g2v1[g2v1<qt2[2]])
length(g2v1[g2v1<qt2[3]])
#similarly for g2v2
输出必须是data.frame，如：
# group value1.25.ct value1.50.ct value1.75.ct value2.25.ct value2.50.ct value2.75.ct
# 1 2 2 4 1 1 4
# 2 1 4 5 2 5 5
请推荐一种有效的方法。谢谢。