我正在使用以下内容处理Web应用程序:
我正在尝试通过LDAP领域对用户进行身份验证。
我使用以下值测试了使用JXplorer的登录:
现在我的问题:
我必须对不是基于GET
而是基于cn
的用户进行身份验证。
然而,这不会起作用。
我公司的LDAP-Admin建议的工作流程:
我有一个系统用户(据我所知)应该连接到LDAP服务器,根据给定的uid
搜索用户并返回该用户的uid
。
在第二步中,应该可以使用cn
对用户进行身份验证,就像在JXplorer中完成(成功)一样。
对于我的测试LDAP,我的shiro.ini配置看起来像这样(不是我现在想要验证的那个)
cn
我现在面临的问题是,我找不到有关如何配置shiro.ini文件的信息,以便从上面算出建议的工作流程。
问题#1
我可以使用标准ldapRealm = org.apache.shiro.realm.ldap.JndiLdapRealm
ldapRealm.userDnTemplate = cn={0},ou=People,dc=maxcrc,dc=com
ldapRealm.contextFactory.url = ldap://localhost:389
(我该如何配置它)?特别是对于证书的整合,我找不到合适的东西。
问题#2
我是否需要为此“2步验证”创建自定义JndiLdapRealm,这样的Realm看起来如何?
答案 0 :(得分:1)
我找到了一个解决方案,那就是从getUserDN()
JndiLdapRealm
方法
现在看起来像这样:
/**
* Addition to standard shiro code
* User logs in with his {@link principal} (username) but login needs to be performed with his cn instead
* The addition is an ldap query to get the users cn from the ldap server and store it (instead of the given principal) in the return String
* @return UserDN with user uid (cn) instead of principal (username)
*/
@Override
protected String getUserDn( final String principal ) throws IllegalArgumentException, IllegalStateException {
if (!StringUtils.hasText(principal)) {
throw new IllegalArgumentException("User principal cannot be null or empty for User DN construction.");
}
String prefix = getUserDnPrefix();
String suffix = getUserDnSuffix();
if (prefix == null && suffix == null) {
log.debug("userDnTemplate property has not been configured, indicating the submitted " +
"AuthenticationToken's principal is the same as the User DN. Returning the method argument " +
"as is.");
return principal;
}
int prefixLength = prefix != null ? prefix.length() : 0;
int suffixLength = suffix != null ? suffix.length() : 0;
StringBuilder sb = new StringBuilder(prefixLength + principal.length() + suffixLength);
if (prefixLength > 0) {
sb.append(prefix);
}
/*############################################################################################
* ADDITION TO STANDARD SHIRO CODE
* User logs in with his {@link principal} (username) but login needs to be performed with his cn instead
* => translate username to cn
*/
AppSettings_Controler settings = Startup.getAppSettingsControler();
LDAP_Manager ldap_manager = new LDAP_Manager();
LdapContext ctx = ldap_manager.getLdapConnection();
String user_uid = "";
SearchControls constraints = new SearchControls();
constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);
String[] attrIDs = {"cn"};
constraints.setReturningAttributes(attrIDs);
NamingEnumeration answer = null;
try{
answer = ctx.search(settings.get_ldap_search_dn_1(), settings.get_ldap_uname_field_name_1() + "=" + principal, constraints);
if (answer.hasMore()) {
Attributes attrs = ((SearchResult) answer.next()).getAttributes();
user_uid = attrs.get("cn").toString().substring(attrIDs[0].length() + 2);
} else {
throw new Exception("Invalid User");
}
} catch (Exception ex) {
// Error Handling & Fallback to my second LDAP-Server
try{
answer = ctx.search(settings.get_ldap_search_dn_2(), settings.get_ldap_uname_field_name_2() + "=" + principal, constraints);
if (answer.hasMore()) {
Attributes attrs = ((SearchResult) answer.next()).getAttributes();
user_uid = attrs.get("cn").toString().substring(attrIDs[0].length() + 2);
} else {
throw new Exception("Invalid User");
}
}catch (Exception exe) {
// Error Handling
}
}
try {
ctx.close();
} catch (NamingException ex) {
JndiLdapRealm_custom_error_logger.error("getUserDn(); Fehler beim schließen: ", ex);
}
//############################################################################################
//############################################################################################
// Shiro Standard Code -> add principal to String
//sb.append(principal);
/*############################################################################################
/*############################################################################################
* ALTERED CODE
* Instead -> Add user's cn to String
*/
sb.append(user_uid);
//############################################################################################
if (suffixLength > 0) {
sb.append(suffix);
}
return sb.toString();
}
此添加执行LDAP-Query以根据提供的用户名获取用户uid(cn)。这样,登录就可以与用户一起输入我的应用程序的LDAP-Username,并遵循上述工作流程。
如果您有任何建议或意见,请不要犹豫,将它们发布在这里;)