Question

从文件中读取行作为字符串并且string.contains（“someexamplestring”）将返回区分大小写的字符串的输出。

如果行中有“someExampleString”，则不会返回。

如何以不区分大小写的方式识别字符串？

Answer 1

实际上，这是How to check if a String contains another String in a case insensitive manner in Java?

的副本

如果您的要求比较简单并只处理英文字母，您可以按照以下答案进行操作。

你应该string.toLowerCase().contains("someExampleString".toLowerCase());。

从Java SE文档中了解有关public String toLowerCase()的更多信息。

此外，正如问题的评论部分中Artur Biesiadowski暗示的那样，请在此处重新进行迭代：

关于所有建议toLowerCase / toUpperCase - 的答案如果你超出ASCII空间 ，请小心。有一些语言从低到高和向后（或其他方式）不是是一致的。土耳其人无家可归＆＃39; i＆＃39;我想到了：Dotted and dotless I

另外，为了使其更安全，您可以使用其他方法 toLowerCase(Locale.English) 并始终将语言环境覆盖为英语。但是，限制是你不再国际化了。

string.toLowerCase(Locale.English).contains("someExampleString".toLowerCase(Locale.English));

Answer 2

首先在输入字符串上使用String.toLowerCase(str)方法，然后应用String.contains(str)方法。

Answer 3

要实现不区分大小写的操作，我们需要将一种格式的字符串设置为大写或小写。toLowerCase或'toUpperCase'方法在您想要包含操作时会很有用

toLowerCase中有两种变体。

somestring.toLowerCase();
somestring.toLowerCase(Locale somelocale)

实施例

String case1 = "StackOverFlow";
String case2 = "STACKOverfloW";
bool isSame ;
isSame = case1.toLowerCase().Contains(case2.toLowerCase());

请注意，当您想比较两个字符串时，equalsIgnoreCase()会很有用

Answer 4

您可以使用正则表达式：

str.matches("(?i).*someexamplestring.*")

Answer 5

您可以toLowerCase()使用您的字符串，然后使用您想要匹配的较低版本的contains进行[]。

Answer 6

您应该将两个字符串转换为小写或大写。然后做手术。

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String.contains方法的替代方法是什么是不区分大小写的？

6 个答案: