Question

当我使用Spring datajpa和Hibenate来阅读Oracle时，我遇到了一个错误，我会说明这个：

Oracle表名包含特殊字符（双引号），因此，我必须使用SELECT * FROM "Graph" WHERE "ID"=1。
因此，当我使用hibernate编写实体类时，我必须指出它的特殊名称。

这是用于创建"Graph"表的ddl：

CREATE TABLE "ATLASCOPCO_TOOLSNET"."Graph" (
"ID" NUMBER(19) NOT NULL ,
"ResultID" NUMBER(19) NOT NULL ,
"GraphTypeID" NUMBER(19) NOT NULL ,
"SampleTime" BINARY_FLOAT NOT NULL ,
"AngleOffset" BINARY_FLOAT NOT NULL ,
"GraphValues" BLOB NOT NULL ,
"AngleFactor" BINARY_DOUBLE NULL ,
"TorqueFactor" BINARY_DOUBLE NULL ,
"StartTime" BINARY_FLOAT NULL ,
"EndTime" BINARY_FLOAT NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

当我使用正常的表名时：

@Entity
@Table(name = "Graph")
@Getter
@Setter
public class Graph {
    @Id
    @Column(name = "ID\"")
    private Long id;

    @Column(name = "ResultID")
    private Long resultId;

    @Column(name = "GraphTypeID")
    private Long graphTypeID;

    @Column(name = "SampleTime")
    private BINARY_FLOAT sampleTime;

    @Column(name = "AngleOffset")
    private BINARY_FLOAT angleOffset;

    @Column(name = "GraphValue")
    private byte[] graphValue;

    @Column(name = "AngleFactor")
    private BINARY_DOUBLE angleFactor;

    @Column(name = "TorqueFactor")
    private BINARY_DOUBLE torqueFactor;

    @Column(name = "StartTime")
    private BINARY_FLOAT startTime;

    @Column(name = "EndTime")
    private BINARY_FLOAT endTime;
}

我收到错误：Caused by: java.sql.SQLSyntaxErrorException: ORA-00972: identifier is too long

当我使用它时：

@Entity
@Table(name = "\"Graph\"")
@Getter
@Setter
public class Graph {
    @Id
    @Column(name = "\"ID\"\"")
    private Long id;

    @Column(name = "\"ResultID\"")
    private Long resultId;

    @Column(name = "\"GraphTypeID\"")
    private Long graphTypeID;

    @Column(name = "\"SampleTime\"")
    private BINARY_FLOAT sampleTime;

    @Column(name = "\"AngleOffset\"")
    private BINARY_FLOAT angleOffset;

    @Column(name = "\"GraphValue\"")
    private byte[] graphValue;

    @Column(name = "\"AngleFactor\"")
    private BINARY_DOUBLE angleFactor;

    @Column(name = "\"TorqueFactor\"")
    private BINARY_DOUBLE torqueFactor;

    @Column(name = "\"StartTime\"")
    private BINARY_FLOAT startTime;

    @Column(name = "\"EndTime\"")
    private BINARY_FLOAT endTime;
}

我得到了Caused by: java.sql.SQLSyntaxErrorException: ORA-00911: invalid character

Answer 1

删除列名中的特殊字符\"，这会导致问题。 JPA和Oracle驱动程序将正确处理所有内容。

您可以省略"，ANSI SQL也可以。

CREATE TABLE NEW_TABLE (ID NUMBER(19) NOT NULL , NAME VARCHAR2(19) NOT NULL);

Answer 2

假设您的表格中的列名称为＆＃34; id＆＃34; ，如下所示：

然后要使用特殊字符（＆＃34; ），您需要添加转义序列，如下所示：

    @Column(name="`\"id\"`")
    private int id;

结果将是一个名称为（＆＃34; id＆＃34; ）的列。
请找到以下更新的Graph POJO类：

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table (name="`\"Graph\"`")
@Getter
@Setter
public class Graph {
@Id
@Column (name="`\"ID\"`")
private Long id;

@Column (name="`\"ResultID\"`")
private Long resultId;

@Column(name="`\"GraphTypeID\"`")
private Long graphTypeID;

@Column (name="`\"SampleTime\"`")
private BINARY_FLOAT sampleTime; 

@Column (name="`\"AngleOffset\"`")
private BINARY_FLOAT angleOffset;

@Column (name="`\"GraphValue\"`")
private byte[] graphValue;

@Column (name="`\"AngleFactor\"`")
private BINARY_DOUBLE angleFactor;

@Column (name="`\"TorqueFactor\"`")
private BINARY_DOUBLE torqueFactor;

@Column (name="`\"StartTime\"`")
private BINARY_FLOAT startTime;

@Column (name="`\"EndTime\"`")
private BINARY_FLOAT endTime;
}

要从Graph表中检索数据，请使用Hibernate中的以下代码：

Query query=session.createSQLQuery("SELECT * FROM `\" Graph \"` WHERE `\"ID\"`=1 ");

希望这会对你有所帮助。

Hibernate和Spring DataJPA无法处理具有特殊字符的Oracle表名？

2 个答案: