Question

我有SQL Server工作。我有超过20000行使用SQL server.I有列Filed Name Amount。 in Amount Filed Inserted negative and Positive Number。现在我想要Sort Amount字段负数和正数

示例：

Entity  ExpenseTypeCode ExpenseType  Amount

  11       043            Hotel        5

  12       044            travel       23

  13       045            drink        55

  14       046            Dinner       23

  15       047            airline      556

  16       048            Hotel        -5

我如何喜欢超过30000个LINES。在我的表中我有费用类型但负值和正值我想要排序我的表像负面和正面顺序相同的值

Entity ExpenseTypeCode ExpenseType Amount

  11       043            Hotel        5

  16       048            Hotel        -5 --> Want sort like this 

  12       044            travel       23

  13       045            drink        55

  14       046            Dinner       23

  15       047            airline      556

我怎样才能对表格进行排序？

Answer 1

在排序中使用 ABS功能：

ABS（）：它会将您的负值转换为正值

SELECT
    *
FROM TableName 
Order BY ABS(Amount),Amount*-1

如果您想要负值和正值相同且订单先考虑为正，那么：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Graph</title>
</head>
<body>
<script src="../node_modules/angular/angular.min.js"></script>
<script src="../node_modules/chart.js/Chart.min.js"></script>
<script src="../node_modules/angular-chart.js/dist/angular-chart.min.js"></script>

<script>
    var app = angular.module('app', ['chart.js']);
    app.controller('BarCtrl', ['$scope', function ($scope) {
        $scope.options = { legend: { display: true } };
        $scope.labels = ['2006', '2007', '2008', '2009', '2010', '2011', '2012'];
        $scope.series = ['Series A', 'Series B'];
        $scope.data = [
            [65, 59, 80, 81, 56, 55, 40],
            [28, 48, 40, 19, 86, 27, 90]
        ];
    }]);

</script>
<div ng-app="app" ng-controller="BarCtrl">
<canvas id="bar" chart-type="type"
        chart-data="data" chart-labels="labels"> chart-series="series"
</canvas>
</div>
</body>
</html>

示例：

初始

输出

Answer 2

  select * from @t t 
    order by expensetype,
        case when amount > 0 then 1 else 2 end

结果

Entity      ExpenseTypeCode ExpenseType Amount
----------- --------------- ----------- -----------
         15              47 airline             556
         14              46 Dinner               23
         13              45 drink                55
         11              43 Hotel                 5
         16              48 Hotel                -5
         12              44 travel               23

如果您正在寻找匹配对，那么这样的东西可能就是您想要的

declare @t table(Entity int, ExpenseTypeCode int, ExpenseType varchar(10),  Amount int)
insert into @t values
(  11,       043,            'Hotel'   ,     6),
(  8,       043,            'Hotel'   ,     5),
(  9,       043,            'Hotel'   ,     5),
(  10,       043,            'Hotel'   ,     5),
(  12,       044,            'travel'  ,     23),
(  13,       045,            'drink'   ,     55),
(  14,       046,            'Dinner'  ,     23),
(  15,       047,            'airline' ,     556),
(  16,       048,            'Hotel'   ,     -5),
(  17,       048,            'Hotel'   ,     -5),
(  18,       043,            'Hotel'   ,     -6),
(  19,       043,            'Hotel'   ,     -6)

select t.*,row_number() over(partition by t.ExpenseType, t.amount order by t.entity) rn,t.amount as absamount
from @t t 
where t.amount > 0
union all
select t.*,row_number() over(partition by t.ExpenseTypeCode, t.amount order by t.entity) rn, abs(t.amount)
from @t t 
where t.amount < 0
order by t.expensetype,absamount,rn,t.amount desc

结果

Entity      ExpenseTypeCode ExpenseType Amount      rn                   absamount
----------- --------------- ----------- ----------- -------------------- -----------
         15              47 airline             556                    1         556
         14              46 Dinner               23                    1          23
         13              45 drink                55                    1          55
          8              43 Hotel                 5                    1           5
         16              48 Hotel                -5                    1           5
          9              43 Hotel                 5                    2           5
         17              48 Hotel                -5                    2           5
         10              43 Hotel                 5                    3           5
         11              43 Hotel                 6                    1           6
         18              43 Hotel                -6                    1           6
         19              43 Hotel                -6                    2           6
         12              44 travel               23                    1          23

或可能是完整的加入

select  s.*,t.* from
(
select t.*,row_number() over(partition by t.ExpenseType, t.amount order by t.entity) rn
from @t t 
where t.amount > 0
) s
full join
(
select t.*,row_number() over(partition by t.ExpenseTypeCode, t.amount order by t.entity) rn
from @t t 
where t.amount < 0
) t on t.expensetype = s.expensetype and t.rn = s.rn and abs(t.amount) = s.amount
order by s.expensetype

Entity      ExpenseTypeCode ExpenseType Amount      rn                   Entity      ExpenseTypeCode ExpenseType Amount      rn
----------- --------------- ----------- ----------- -------------------- ----------- --------------- ----------- ----------- --------------------
       NULL            NULL NULL               NULL                 NULL          19              43 Hotel                -6                    2
         15              47 airline             556                    1        NULL            NULL NULL               NULL                 NULL
         14              46 Dinner               23                    1        NULL            NULL NULL               NULL                 NULL
         13              45 drink                55                    1        NULL            NULL NULL               NULL                 NULL
         11              43 Hotel                 6                    1          18              43 Hotel                -6                    1
         10              43 Hotel                 5                    3        NULL            NULL NULL               NULL                 NULL
          8              43 Hotel                 5                    1          16              48 Hotel                -5                    1
          9              43 Hotel                 5                    2          17              48 Hotel                -5                    2
         12              44 travel               23                    1        NULL            NULL NULL               NULL                 NULL

如何在SQL Server中对数量负数和正数进行排序

2 个答案: