Question

以下是我为数组中每个电话号码保存消息的编码在测试中，我已将消息设为欢迎使用所有和5个电话号码进入SMSDTO

如何为数据库中的每个电话号码保存欢迎使用所有消息

1欢迎来到所有9964289813 2欢迎所有9593754589 3欢迎所有9964289444 4欢迎所有9964458454

Pojo课程

@Entity
@Table(name = "sms")
public class SMSDTO {
    @Id
    @GenericGenerator(name = "j", strategy = "increment")
    @GeneratedValue(generator = "j")
    @Column(name = "id")
    private int id;
    @Column(name = "message")
    private String message;
    @Column(name = "phoneNumber")
    private String[] phonenumebr;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getMessage() {
        return message;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public String[] getPhonenumebr() {
        return phonenumebr;
    }

    public void setPhonenumebr(String[] phonenumebr) {
        this.phonenumebr = phonenumebr;
    }

}

主要课程

public class Test {
public static void main(String[] args) {
    SMSDTO sms = new SMSDTO();
    String [] sArry=new String[] { "9964289813", "9591237001", "8722922982", "9611704698", "9900598503" };  
    Configuration c = new Configuration();
    c.configure("/hibernate.cfg.xml");
    SessionFactory sf = c.buildSessionFactory();
    Session s = sf.openSession();
    Transaction tx = s.beginTransaction();
    try {
        for (int i = 0; i < sArry.length; i++) {
            sms.setMessage("welcome to All");
            sms.setPhonenumebr(sArry[i]);
            s.save(sms);
        }

        tx.commit();
    } catch (Exception e) {
        tx.rollback();
    }

}

}

Answer 1

更改 POJO 课程，如下所示：

private String phonenumebr;

public String getPhonenumebr() {
    return phonenumebr;
}
public void setPhonenumebr(String phonenumebr) {
    this.phonenumebr = phonenumebr;
}

只需将private String[] phonenumebr;更改为private String phonenumebr;，因为您有一个String数组，稍后您将在主程序中设置单个值phoneNumber。这可以使用String类型的phonenumebr存储，因为String是一个字符数组。

更改主要方法，如下所示：

public static void main(String[] args) {
    Session session = null;
    Transaction tx = null;
    try {

        Configuration c = new Configuration();
        c.configure("/hibernate.cfg.xml");
        SessionFactory sf = c.buildSessionFactory();
        session = sf.openSession();

        SMSDTO sms =null;
        String [] sArry=new String[] { "9964289813", "9591237001", "8722922982", "9611704698", "9900598503" };  
        tx = session.beginTransaction();
        for (int i = 0; i < sArry.length; i++) {
            sms= new SMSDTO();
            sms.setMessage("welcome to All");
            sms.setPhonenumebr(sArry[i]);
            session.save(sms);
        }
        tx.commit();

    } catch (RuntimeException e) {
        try {
            tx.rollback();
        } catch (RuntimeException rbe) {
            System.err.println("Couldn’t roll back transaction"+ rbe);
       }
        throw e;
    } finally{
        if(session != null){
            session.close();
        }
    }

    System.out.println("entries saved...");
}

输出：

如何在hibernate中保存到值数组

1 个答案: