Question

我有一个NSArray<NSString*>*对象，我需要调用一个C API，它接受一个字符串数组char**。

最好的方法是什么？重要的注意事项是c字符串不能包含const修饰符，因此以下内容不够好UTF8String返回const char*：

NSArray<NSString*>* names = ...;
int len = args.count;
char* cNames[len];
for( int i = 0; i < len; i++ ) {
    cNames[i] = names[i].UTF8String;
};

Answer 1

你需要做一些动态内存，因为你不能依赖正在发布的UTF8String的后备内存。

NSArray *strings = @[ @"String 1", @"Other string", @"Random String"];
char **cStrings = NULL;
NSInteger numCStrings = strings.count;

if (numCStrings) {
    cStrings = (char **)calloc(numCStrings, sizeof(char*))  ;

    if (cStrings) {
        // Safer to allocate memory for each string

        for (NSInteger i=0;i<numCStrings;i++) {
            NSString *nsString = strings[i];
            char *cString = (char *)malloc([nsString lengthOfBytesUsingEncoding:NSUTF8StringEncoding] + 1); // + 1 for \0

            if (cString) {
                strcpy(cString, nsString.UTF8String);
                cStrings[i] = cString;
            } else {
                // You should handle your error
            }
        }
    } else {
        // You should handle your error
    }
}

for (NSInteger i=0;i<numCStrings;i++) {
    NSLog(@"C-String (%ld): %s", i, cStrings[i]);
}

// Note you need to free your memory later!
// Do any additional setup after loading the view, typically from a nib.
for (NSInteger i=0;i<numCStrings;i++) {
    if (cStrings[i]) {
        // Free each string
        free(cStrings[i]);
    }
}

// Free the array
free(cStrings);

cStrings = NULL;
numCStrings = 0;

如何将NSString数组转换为c-strings数组？

1 个答案: