Question

我需要使用GDB来监视具有相同名称的两个不同变量，其中一个是全局变量，而另一个是局部变量。任何解决方案？

Answer 1

考虑以下示例：

int foo;

void bar()
{
  foo++;
}

int main()
{
  int foo;
  for (foo = 0; foo < 5; foo++) {
    bar();
  }
  return 0;
}

gcc -g t.c
gdb -q ./a.out

(gdb) start
Temporary breakpoint 1 at 0x40050a: file t.c, line 11.
Starting program: /tmp/a.out 

Temporary breakpoint 1, main () at t.c:11
11    for (foo = 0; foo < 5; foo++) {
(gdb) p &foo
$1 = (int *) 0x7fffffffdccc
(gdb) watch -l foo
Hardware watchpoint 2: -location foo

注意：以上观察设置在本地foo。

(gdb) p &::foo
$2 = (int *) 0x60103c <foo>
(gdb) watch -l ::foo
Hardware watchpoint 3: -location ::foo

注意：上面的观看是在全局foo上设置的。

(gdb) c
Continuing.
Hardware watchpoint 3: -location ::foo

全局foo已在bar()内进行了调整。

Old value = 0
New value = 1
bar () at t.c:6
6   }
(gdb) c
Continuing.
Hardware watchpoint 2: -location foo

本地foo已在main内修改：

Old value = 0
New value = 1
0x0000000000400521 in main () at t.c:11
11    for (foo = 0; foo < 5; foo++) {
(gdb) c
Continuing.
Hardware watchpoint 3: -location ::foo

Old value = 1
New value = 2
bar () at t.c:6
6   }
(gdb) c
Continuing.
Hardware watchpoint 2: -location foo

Old value = 1
New value = 2
0x0000000000400521 in main () at t.c:11
11    for (foo = 0; foo < 5; foo++) {

......等等。

如何使用GDB监视具有相同名称的两个不同变量

1 个答案: