Question

我有一个运行的命令，它提供如下输出：

{
"endpointApplications": {
    "App_Name": {
        "connectionState": "Disconnected",
        "connectionTime": "No connection was established",
        "linkAttributes": {
            "ackSettings": {
                "dataAckEnabled": "true",
                "dataAckTimeout": "5000",
                "dataNakRetryLimit": "0",
                "retransmitDelay": "500"
            },
            "keepAliveSettings": {
                "keepAliveAckTimeout": "5000",
                "keepAliveInterval": "30000"
            },
            "logTraffic": "false",
            "port": "9999",
            "role": "server"
        },
        "protocol": "snmp"
    }
},
"queueStats": {}
}

我需要输出如下所示：

{"endpointApplications": {"app_name": {"connectionState": "Disconnected","connectionTime": "No connection was established","linkAttributes": {"ackSettings":{"dataAckEnabled": "true","dataAckTimeout": "5000","dataNakRetryLimit": "0","retransmitDelay": "500"},"keepAliveSettings":{"keepAliveAckTimeout": "5000","keepAliveInterval": "30000"},"logTraffic": "false","port": "9999","role": "server"},"protocol": "snmp"}},"queueStats":{}}

我尝试使用awk和sed结合不同的参数，但我无法在不丢失JSON格式的情况下开始工作。

Answer 1

你应该使用jq这样的东西：

jq -c . input.txt

使用sed＆amp; tr：

sed -e 's/^ *//' < input.txt | tr -d '\n'

虽然我建议使用专为操作JSON而设计的jq。对于JSON，jq与sed类似。使用sed / awk / etc以文本方式操作JSON不能保证生成语义上等效的JSON。

Answer 2

jq或任何其他json识别工具最适合json文件操作。但此处基于awk的解决方案。

awk -v RS= '{$1=$1}1' input.json
{ "endpointApplications": { "App_Name": { "connectionState": "Disconnected", "connectionTime": "No connection was established", "linkAttributes": { "ackSettings": { "dataAckEnabled": "true", "dataAckTimeout": "5000", "dataNakRetryLimit": "0", "retransmitDelay": "500" }, "keepAliveSettings": { "keepAliveAckTimeout": "5000", "keepAliveInterval": "30000" }, "logTraffic": "false", "port": "9999", "role": "server" }, "protocol": "snmp" } }, "queueStats": {} }

注意：此解决方案主要针对没有像jq这样的工具的旧系统，并且由于某些原因没有机会安装它们。

将JSON漂亮打印转换为一行

2 个答案: