Question

以下查询效果很好。但是，我想修改它。

我希望when s.topten = 1 then 0 else 1 end的排序只能在s.datesubmitted距现在不到24小时的时候完成。

我该怎么做？

提前致谢，

约翰

$sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, s.datesubmitted, l.username,
  s.submissionid, s.subcheck, s.topten, COUNT(c.commentid) countComments, 
  GREATEST(s.datesubmitted, COALESCE(MAX(c.datecommented), s.datesubmitted)) AS most_recent
FROM submission s
INNER JOIN login l ON s.loginid = l.loginid
LEFT OUTER JOIN comment c ON s.submissionid = c.submissionid
GROUP BY s.submissionid
ORDER BY case when s.topten = 1 then 0 else 1 end, most_recent DESC 
LIMIT $offset, $rowsperpage";

Answer 1

添加另一个WHEN子句，用于检查间隔并生成-1。

Answer 2

使用：

    SELECT s.loginid, s.title, s.url, s.displayurl, s.datesubmitted, l.username,
           s.submissionid, s.subcheck, s.topten, COUNT(c.commentid) countComments, 
           GREATEST(s.datesubmitted, COALESCE(MAX(c.datecommented), s.datesubmitted)) AS most_recent
      FROM submission s
      JOIN login l ON s.loginid = l.loginid
 LEFT JOIN comment c ON s.submissionid = c.submissionid
  GROUP BY s.submissionid
  ORDER BY CASE 
             WHEN s.datesubmitted > DATE_SUB(NOW(), INTERVAL 1 DAY) AND s.topten = 1 THEN 0 
             WHEN s.datesubmitted > DATE_SUB(NOW(), INTERVAL 1 DAY) AND s.topten != 1 THEN 1
             ELSE 2 
           END, most_recent DESC 
     LIMIT $offset, $rowsperpage

使查询排序条件取决于变量的年龄

2 个答案: