JOOQ插入类型

时间:2016-09-22 18:54:59

标签: java postgresql jooq

我在Spring 4应用程序中使用jOOQ 3.8.4和PostgreSQL 9.5。我有以下表格和类型定义

 CREATE DOMAIN shop.money_amount AS numeric(6,2) DEFAULT 0 NOT NULL CHECK (value > 0::numeric);

 CREATE TYPE shop.money AS (
   m_amount shop.money_amount,
   m_currency shop.currency,
   m_country shop.site_country
 );

 CREATE TYPE shop.money_mapping AS (
   mm_moneys shop.money []
 );

 CREATE TABLE shop.article
 (
   a_id bigserial NOT NULL,
   a_price shop.money_mapping NOT NULL,
   CONSTRAINT a_pk_id PRIMARY KEY (a_id)
 );

然后我尝试使用jOOQ进行插入,即:

MoneyMappingRecord priceMoneyMapping = new MoneyMappingRecord();
priceMoneyMapping.setMoneys(new MoneyRecord[]{
        new MoneyRecord().setAmount(new BigDecimal("11")).setCountry(SiteCountry.US).setCurrency(Currency.USD),
        new MoneyRecord().setAmount(new BigDecimal("14")).setCountry(SiteCountry.DE).setCurrency(Currency.EUR)
});

dsl.insertInto(ARTICLE)
        .set(ARTICLE.A_PRICE, priceMoneyMapping)
        .returning(ARTICLE.A_ID).fetchOne().getId();

然后我得到:

Caused by: org.springframework.jdbc.BadSqlGrammarException: jOOQ; 
  bad SQL grammar [insert into "shop"."article" ("a_price") values
  (row(?::money[])) returning "shop"."article"."a_id"]; nested 
  exception is org.postgresql.util.PSQLException: 
  ERROR: cannot cast type record to shop.money_mapping
  Detail: Cannot cast type money[] to shop.money[] in column 1.

我做错了什么?

更新

我尝试按照Lukas的建议重命名shop.money类型(从shop.moneyshop.localized_money),但我相信问题与架构有关。请参阅更新的错误。

Caused by: org.springframework.jdbc.BadSqlGrammarException: 
   jOOQ; bad SQL grammar [insert into "shop"."article" ("a_price") 
   values (row(?::localized_money[])) returning "shop"."article"."a_id"]; nested exception is    
   org.postgresql.util.PSQLException: ERROR: type "localized_money[]" does not exist

类型中的类型可能是个问题!

1 个答案:

答案 0 :(得分:1)

在jOOQ 3.8中,似乎存在与嵌套数组类型相关的问题。我为此创建了一个问题:https://github.com/jOOQ/jOOQ/issues/5571

问题是当绑定为绑定变量时,您的自定义类型数组类型需要完全限定。如果它不是完全限定的,那么PostgreSQL找不到该类型。此问题中描述了一种可能的解决方法:Permanently Set Postgresql Schema Path

您可以在用户的​​搜索路径中添加shop架构:

ALTER ROLE <your_login_role> SET search_path TO shop;

...这意味着shop架构内的元素不再需要完全限定。这也可能是件坏事,所以要小心! :)