Question

我想要做的是将所有客户账单合并为一个，所以不是“鲸鱼市场”出现三次不同的值，我希望“鲸鱼市场有一个总价值，总数将是{{1 }}

我尝试使用25968.75和DISTINCT来显示重复的值。

GROUP BY：

DISTINCT

SELECT DISTINCT CLIENTNAME AS "Client", HOURSWORKED*CHARGERATE AS "Total Billable" FROM EMPLOYEE WHERE CLIENTNAME IS NOT NULL ORDER BY "Total Billable" DESC;：

GROUP BY

两种方法都提供相同的输出：

SELECT CLIENTNAME AS "Client", HOURSWORKED*CHARGERATE AS "Total Billable"
FROM EMPLOYEE
WHERE CLIENTNAME IS NOT NULL
GROUP BY CLIENTNAME, HOURSWORKED*CHARGERATE
ORDER BY "Total Billable" DESC;

Answer 1

您可能想要使用聚合函数：

SELECT CLIENTNAME AS "Client", SUM(HOURSWORKED*CHARGERATE) AS "Total Billable"
FROM EMPLOYEE
WHERE CLIENTNAME IS NOT NULL
GROUP BY CLIENTNAME
ORDER BY "Total Billable" DESC;

Answer 2

你需要：

SELECT CLIENTNAME AS "Client", SUM(HOURSWORKED*CHARGERATE) AS "Total Billable"
FROM EMPLOYEE
WHERE CLIENTNAME IS NOT NULL
GROUP BY CLIENTNAME
ORDER BY "Total Billable" DESC;

DISTINCT或GROUP BY语句没有删除重复项？

2 个答案: