Question

基本上，我想自动检查数据库中是否存在电子邮件。 connection.php＆amp;已插入mysqli个查询。

HTML：

<input type="email" name="email" class="formEmail">

JS：

  $( document ).ready(function() {
    $('.formEmail').on('change', function() {
        //ajax request
        $.ajax({
            url: "queries/checkEmail.php",
            data: {
                'email' : $('.formEmail').val()
            },
            dataType: 'json',
            success: function(data) {
                if(date == true) {
                    alert('Email exists!');
                }
                else {
                    alert('Email doesnt!');
                }
            },
            error: function(data){
                //error
            }
        });
    });
  });

PHP：

require_once("../connection.php");

$userEmail = $_GET['email'];

$checkEmail=mysqli_query($con, "SELECT email from accounts WHERE email='$userEmail'");

if (mysqli_num_rows($checkEmail) == 1) {
  $response = true;
} else {
  $response = false;
}

echo json_encode($response);

Answer 1

在select c.consumerid, signupdate, state, year(DOB), topaffiliate, activestatus, lastuseddate, IFNULL(Total_ACH, 0) AS Total_ACH, IFNULL(Bill_Pay, 0) AS Bill_Pay, IFNULL(Revenue, 0) AS Revenue, IFNULL(Cash__TXNs, 0) AS Cash__TXNs, ... FROM consumerdata AS c LEFT JOIN ( SELECT consumerid, SUM(transactionamount) AS Total_ACH FROM achload GROUP BY consumerid) AS a ON a.consumerid = c.consumerid LEFT JOIN ( SELECT consumerid, SUM(transactionamount) AS Bill_Pay FROM billpay GROUP BY consumerid) AS b ON b.consumerid = c.consumerid LEFT JOIN ( SELECT consumerid, SUM(transactionamount) AS Revenue FROM recharge GROUP BY consumerid) AS r ON r.consumerid = c.consumerid LEFT JOIN ( SELECT consumerid, COUNT(*) AS Cash__TXNs FROM Cash GROUP BY consumerid) AS cash ON cash.consumerid = c.consumerid ... WHERE c.signupdate between DATE(20120101) and CURDATE() ORDER BY signupdate ASC调用函数的成功块中，if条件中的响应得到了一个小错误。

在条件
中将ajax重写为date

data

Answer 2

当您使用ajax并且输出是JSON时，您只需要发送纯JSON输出，请检查以下代码。我在checkEmail.php文件中添加了JSON消息的头文件，因此可以通过javascript轻松读取

<强>代码

<?php
require_once("../connection.php");

$userEmail = $_GET['email'];

$checkEmail=mysqli_query($con, "SELECT email from accounts WHERE email='$userEmail'");

if (mysqli_num_rows($checkEmail) == 1) {
  $response = true;
} else {
  $response = false;
}

//Here your required to set the header which will make output as pure JSON output and easy to read by javascript

header('Content-Type:application/json;');
echo json_encode($response);

Answer 3

我想你忘了在Ajax中添加请求方法：type:'post' 当然，在PHP中修复：将GET更改为POST

使用ajax检查电子邮件是否存在

3 个答案: