我在做如下。我们的想法是根据菜单按钮提供的类型传递不同的值并显示数据。
但它没有按预期工作。 它只是显示首先调用哪个视图(或者在第二个按钮按下时不刷新数据显示第一个视图)。 那么这样做的正确方法是什么?
if (indexPath.row == 1) {
SomeViewController* v = [self.storyboard instantiateViewControllerWithIdentifier:@"storyboardCat"];
v.type=@"1";
[self showViewController:v];
[self.slidingViewController resetTopViewAnimated:YES];
}
if (indexPath.row == 2) {
SomeViewController* v = [self.storyboard instantiateViewControllerWithIdentifier:@"storyboardCat"];
v.type=@"2";
[self showViewController:v];
[self.slidingViewController resetTopViewAnimated:YES];
}
编辑 - 了解更多信息 SomeViewController.h文件
@interface SomeViewController : UIViewController
@property (nonatomic, strong) NSString *type;
@end
SomeViewController.m文件
@implementation SomeViewController
@synthesize type;
arrayData = [NSMutableArray arrayWithArray:[CoreDataController getSomeData:type]];
//so trying to populate different values in tableview based on passed parameter to function
但是现在哪个视图被调用为first或者值被传递(1或2),只有那些值被填充,并且值不会在同时调用时传递另一个值(例如,当index row为2时)。
答案 0 :(得分:0)
试试这个
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Main" bundle: nil]; //Change Main if your storyboard name is different.
SomeViewController* v = [storyboard instantiateViewControllerWithIdentifier:@"launchView"]; // launchView is the name given to the view controller in the properties as shown in below screenshot
希望这有帮助