邮寄请求网址应按以下格式更新。
https://www.example.com/api/one-push?type=json&query=push&title=____&url=____&tag=___
<form ng-submit="submitUrl()">
<input type="text" class="form-control block" ng-model="url.title" placeholder="title">
<input type="text" class="form-control block" ng-model="url.urlString" placeholder="url">
<input type="text" class="form-control block" ng-model="url.tag" placeholder="tag">
<button>Add</button>
</form>
var app = angular.module('app', [])
.controller('searchController', ['$scope', '$http','searchService', function($scope, $http,searchService) {
$scope.submitUrl = function() {
$scope.url = {};
searchService.updateUrl($scope.url).success(function(data) {
$scope.url = data;
})
}
}]);
app.factory('searchService',function($http) {
var url = " https://www.example.com/api/one-push?";
var Info = {};
Info.updateUrl = function(url) {
return $http.post(url, {
type: "json",
url: url.title,
urlString: url.urlString,
tag: url.tag
});
}
return Info;
});
答案 0 :(得分:0)
您可以使用&#34; params&#34;实现这一点如下。
app.factory('searchService',function($http) {
var url = " https://www.example.com/api/one-push?";
var Info = {};
Info.updateUrl = function(url) {
return $http.post(url, {
type: "json",
params: {'type':'json','query':'push','title':title,'url':url,'tag':tag}
});
}
return Info;
});
答案 1 :(得分:0)
$ http.post方法的签名是post(url, data, [config])
此处配置是可选的
由于您希望在发布请求时将数据作为查询字符串传递,因此您必须在配置对象上设置params
属性。
厂:
app.factory('searchService',function($http) {
var url = " https://www.example.com/api/one-push";
var Info = {};
Info.updateUrl = function(url, data) {
var _data = data || {};
return $http.post(url, _data, {
responseType: "json",
// Pass the data you want to pass as query params on request
params: {
type: "json",
url: _data.urlString,
query: 'push',
title: _data.title,
tag: _data.tag
}
});
}
return Info;
});