NSArray的多维NSArray？

Question

首先参考下面的图形显示：

我有一个包含9个元素的NSArray。 这9个元素中的每一个都包含另外5个元素。

我想做的是将每个地方的 var strYears = form.years.value; var strMonths = form.months.value; var strDays = form.days.value; var Y = parseInt(strYears); var m = parseInt(strMonths); var q = parseInt(strDays); var h = ""; var output = ""; if (isNaN(Y)) throw ("Incorrect input. Years is not a number."); if (Y < 0 || Y > 9999) throw "Incorrect input. Years is out of expected range (0-9999)."; if (isNaN(m)) throw "Incorrect input. Months is not a number."; if (m < 1 || m > 12) throw "Incorrect input. Months is out of expected range (1-12)."; if (isNaN(q)) throw "Incorrect input. Days is not a number."; if ((q < 1 || q > 31) && (m == 1 || m == 3 || m == 5 || m == 7 || m == 8 || m == 10 || m == 12)) throw "Incorrect input. Days is out of expected range (1-31)."; if ((q < 1 || q > 30) && (m == 4 || m == 6 || m == 9 || m == 11)) throw "Incorrect input. Days is out of expected range (1-30)."; if ((q < 1 || q > 28) && (m == 2) && ( q % 4 === 0 ) && (!( q % 100 ))) throw "Incorrect input. Days is out of expected range (1-28)."; if (m == 1 || m == 2) { m = m + 12; Y = Y - 1; } h = (q + Math.floor(13 * (m + 1) / 5) + Y + Math.floor(Y / 4) - Math.floor(Y / 100) + Math.floor(Y / 400)) % 7; { if (h == 0) h = "Saturday"; if (h == 1) h = "Sunday"; if (h == 2) h = "Monday"; if (h == 3) h = "Tuesday"; if (h == 4) h = "Wednesday"; if (h == 5) h = "Thursday"; if (h == 6) h = "Friday"; var output = h; document.getElementById("output").innerHTML = output; } } catch(error){ document.getElementById("output").innerHTML = "Error: " + error; } }` 带到另一个地方，只包含这些日期。

如何最好地实现？

Answer 1

NSMutableArray * results = [@[] mutableCopy];

for (NSArray *details in self.fuelDetailsForSelectedBike){
    [result addObject:details[1]];
}

Answer 2

这看似相当基本，循环遍历主数组，并为每个对象（即数组）取得它的第二个元素并将其添加到结果中。