exsl:文档无法正常工作

时间:2016-09-22 06:31:37

标签: xml perl xslt exslt

在Windows 7上,我尝试使用Perl v5.8.8和libXSLT 1.66版转换单个文档。这是我的用例的低调版本。

Perl脚本

use strict;
use warnings;
use File::Path;
use File::Spec;
use File::Basename;
use XML::LibXSLT;
use XML::LibXML;
use Getopt::Std;

my $isfile;

my ($xmlfile,$xsltfile,$samplefile) = qw/ Example.xml trans.xsl sample.xml/;
my %opts = ();
getopts('o:',\%opts);

my $outPath = $opts{'o'};
die "Resource Location/Directory not specified" if !defined($outPath);

if(-f $samplefile)
{
    $isfile = "true";
    print "File is present\n";
}
else
{
    $isfile = "false";
    print "File is absent\n";
}

my %args = ( "isfile" => $isfile,"outpath" => $outPath, );
my $xslt = XML::LibXSLT->new;
my $stylesheet = $xslt->parse_stylesheet_file($xsltfile);

     my $security = XML::LibXSLT::Security->new();
     $security->register_callback( read_file  => sub { return 1;} );
     $security->register_callback( write_file => sub { return 1;} );

     $stylesheet->security_callbacks( $security );

my $results  = $stylesheet->transform_file($xmlfile,XML::LibXSLT::xpath_to_string(%{args}));

0;

XSL文件

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xalan="http://xml.apache.org/xslt" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:exsl="http://exslt.org/common" 
    xmlns:date="http://exslt.org/dates-and-times"
    extension-element-prefixes="exsl">

    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" media-type="text/xml"/>

    <xsl:param name="isfile"/>
    <xsl:param name="outpath"/>

    <xsl:variable name="current-year">
        <xsl:value-of select="date:year()"/>
    </xsl:variable>

    <xsl:template match="/">
         <xsl:if test="$isfile = 'true'">
                 <exsl:document href = "{$outpath}" method="xml" version="1.0" encoding="UTF-8" indent="yes">
                 Article:- <xsl:value-of select="exsl:node-set(/Article/Title)|exsl:node-set(/Article/Title)/@context"/>
                Authors:- <xsl:apply-templates select="/Article/Authors/Author"/>
            </exsl:document>
        </xsl:if>
    </xsl:template>

</xsl:stylesheet>

要转换的文件

<?xml version="1.0"?>
<?xml-stylesheet type="xsl" href="trans.xsl"?>
<Article>
  <Title context="This article">My Article</Title>
  <Authors>
    <Author>Mr. Foo</Author>
    <Author>Mr. Bar</Author>
  </Authors>
  <Body>This is my article text.</Body>
</Article>

我事先创建了需要生成文档的目录。然后我运行我的脚本如下

perl Transform.pl -o C:\user\Documents\XSLT\dir1\dir2\output1.xml

未在预期路径中创建文件。相反,当我在DIR目录(我保留转换脚本,xsl文件和输入xml文件)中lsXSLT时,我会得到关注,

%5Cuser%5CDocuments%5CXSLT%5Cdir1%5Cdir2%5Coutput1.xml dir1/ Example.xml sample.xml Transform.pl trans.xsl

但是,当我在选项-o的命令行参数上提供路径时,如下所示,

C:\user\Documents\XSLT\dir1\dir2\output1.xml

文件在适当的提供路径中创建。

1)当我提供Windows特定路径时,为什么exsl-document表现得很奇怪?

2)另外,为什么在路径中添加%5C(相当于/的ASCII)?

3)是否不理解如何将路径分隔符的Windows特定路径解释为/

0 个答案:

没有答案
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