任何人都可以帮我解决这个mysql查询问题
$rela=mysql_query("SELECT *
FROM pvl_posts
WHERE (title LIKE '%$title%' OR post LIKE '%$title%'')
OR (title LIKE '%$post%' OR post LIKE '%$post%'')
AND id != '$id'");
我想用它作为相关文章
答案 0 :(得分:1)
你有一些错误的引号,并使用concat作为类似的字符串
"SELECT *
FROM pvl_posts
WHERE (title LIKE concat('%', '$title','%') OR post LIKE concat('%','$title' ,'%') )
OR (title LIKE concat('%' , '$post', '%') OR post LIKE concat('%','$post','%') )
AND id != '$id'"
答案 1 :(得分:0)
请尝试以下方法:
$rela=mysql_query("SELECT * FROM pvl_posts WHERE (title LIKE '%".$title."%' OR post LIKE '%".$title."%') OR (title LIKE '%".$post."%' OR post LIKE '".$post."') AND id != '".$id."'");
答案 2 :(得分:0)
试试这个,有两个'
,删除它。
$rela=mysql_query("SELECT * FROM pvl_posts WHERE (title LIKE '%$title%' OR post LIKE '%$title%') OR (title LIKE '%$post%' OR post LIKE '%$post%') AND id != '$id'");
答案 3 :(得分:0)
请显示您的mysql连接字符串。这是一个例子:
<?php
$mysqli = new mysqli("localhost", "root", "", "database_name");
$query = "SELECT * FROM pvl_posts WHERE (title LIKE '%$title%' OR post LIKE '%$title%') OR (title LIKE '%$post%' OR post LIKE '%$post%') AND id != '$id'";
$rows = $mysqli->query($query);
if ($rows->num_rows > 0) {
while ($row = $rows->fetch_assoc()) {
// do something with row variable here.
var_dump($row);
}
}
?>
尝试一下。