我想从画廊获取图片。它给我的图像作为位图。我想在.jpg文件中的图像,以便我可以在我的数据库中保存文件名。
我已经按照本教程进行了操作:
http://www.theappguruz.com/blog/android-take-photo-camera-gallery-code-sample
图库图片选择代码:
@SuppressWarnings("deprecation")
private void onSelectFromGalleryResult(Intent data) {
Bitmap bm=null;
if (data != null) {
try {
bm = MediaStore.Images.Media.getBitmap(getApplicationContext().getContentResolver(), data.getData());
} catch (IOException e) {
e.printStackTrace();
}
}
Uri selectedImage = data.getData();
String[] filePath = {MediaStore.Images.Media.DATA};
Cursor c = getContentResolver().query(selectedImage, filePath, null, null, null);
c.moveToFirst();
int columnIndex = c.getColumnIndex(filePath[0]);
String picturePath = c.getString(columnIndex);
c.close();
File file = new File(picturePath);// error line
mProfileImage = file;
profile_image.setImageBitmap(bm);
}
我试过这个。但我在文件上得到空指针。
例外:
Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'char[] java.lang.String.toCharArray()' on a null object reference
此外,我不希望将新创建的文件保存在外部存储中。这应该是一个临时文件。我怎么能这样做?
谢谢..
答案 0 :(得分:1)
好消息是你比你想象的更接近完成了!
Bitmap bm=null;
if (data != null) {
try {
bm = MediaStore.Images.Media.getBitmap(getApplicationContext().getContentResolver(), data.getData());
} catch (IOException e) {
e.printStackTrace();
}
}
此时,如果bm != null
,则您有一个Bitmap对象。 Bitmap是Android的通用图像对象,已准备就绪。它实际上可能已经是.jpg格式,所以你只需将其写入文件即可。你想把它写到一个临时文件,所以我会做这样的事情:
File outputDir = context.getCacheDir(); // Activity context
File outputFile = File.createTempFile("prefix", "extension", outputDir); // follow the API for createTempFile
无论如何,在这一点上,将Bitmap
写入文件非常容易。
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bm.compress(Bitmap.CompressFormat.JPEG, 100, stream); //replace 100 with desired quality percentage.
byte[] byteArray = stream.toByteArray();
现在你有一个字节数组。我会留给你写一个档案。
如果您希望临时文件消失,请参阅此处以获取更多信息:https://developer.android.com/reference/java/io/File.html#deleteOnExit()
Bitmap bm=null;
if (data != null) {
try {
bm = MediaStore.Images.Media.getBitmap(getApplicationContext().getContentResolver(), data.getData());
} catch (IOException e) {
e.printStackTrace();
}
}
if (bm != null) { // sanity check
File outputDir = context.getCacheDir(); // Activity context
File outputFile = File.createTempFile("image", "jpg", outputDir); // follow the API for createTempFile
FileOutputStream stream = new FileOutputStream (outputFile, false); // Add false here so we don't append an image to another image. That would be weird.
// This line actually writes a bitmap to the stream. If you use a ByteArrayOutputStream, you end up with a byte array. If you use a FileOutputStream, you end up with a file.
bm.compress(Bitmap.CompressFormat.JPEG, 100, stream);
stream.close(); // cleanup
}
我希望有所帮助!
答案 1 :(得分:0)
看起来您的private String getRealPathFromURI(Uri uri) {
String[] projection = { MediaStore.Images.Media.DATA };
@SuppressWarnings("deprecation")
Cursor cursor = managedQuery(uri, projection, null, null, null);
int column_index = cursor
.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
为空。这就是你无法转换图像的原因。尝试添加此代码片段以获取所选图像的路径:
onSelectFromGalleryResult
之后,您需要修改String[] filePath = {MediaStore.Images.Media.DATA};
。删除/禁用行 Uri selectedImageUri = Uri.parse(selectedImage);
String photoPath = getRealPathFromURI(selectedImageUri);
mProfileImage = new File(photoPath);
//check if you get something like this - file:///mnt/sdcard/yourselectedimage.png
Log.i("FilePath", mProfileImage.getAbsolutePath)
if(mProfileImage.isExist()){
//Check if the file is exist.
//Do something here (display the image using imageView/ convert the image into string)
}
,依此类推,并替换为以下内容。
iOS 10
问题:您需要以.jpg格式转换它的原因是什么?它可以是.gif,.png等吗?